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lys-0071 [83]
3 years ago
8

Hello! Can I get some help on this? Name the quadrant or axis where each point lies.

Mathematics
1 answer:
hoa [83]3 years ago
4 0

Answer:Instructions: In the figure above, the point with coordinates (4,2) is located in quadrant I. The point with coordinates (-3,4) is located in quadrant II. The point with coordinates (-4,0) is located on the x-axis. The point with coordinates (0, -5) is located on the y-axis.

Step-by-step explanation:

If only the first coordinate is positive, then the point is in quadrant 4. If only the second coordinate is positive, then the point is in quadrant 2. If both coordinates are negative, the point is located in quadrant 3. If one coordinate is zero, then the point is located on the x-axis or the y-axis.

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Find x<br> 1) 3.38 <br> 2)13.99 <br> 3)12.59 <br> 4)16.09
weqwewe [10]
Yes 12-13 hope this helps you
8 0
3 years ago
Plz i need this asap, if you do not know all of them, plz do not answer
Lelechka [254]
1. sqrt 52 = 7.211 rounds to 7

2. irrational number

3. sqrt 441 = 21....rational

4. 12^2 + 3^2 = h^2
    144 + 9 = h^2
     153 = h^2
      sqrt 153 = h
      12.4 = h <===

5. 6^2 + b^2 = 18^2
    36 + b^2 = 324
    b^2 = 324 - 36
    b^2 = 288
    b = sqrt 288
    b = 16.97 rounds to 17 <==

6. 39^2 + 52^2 = c^2
    1521 + 2704 = c^2
    4225 = c^2
    sqrt 4225 = c
    65 = c
    (39 + 52) - 65 = 91 - 65 = 26 miles shorter <==

7. 4^2 + b^2 = 16^2
     16 + b^2 = 256
     b^2 = 256 - 16
     b^2 = 240
     b = sqrt 240
     b = 15.49 rounds to 15.5 <==

8. ?
8 0
4 years ago
I am confused and i dont know how i would do this
Crank

Answer:

5760

Step-by-step explanation:

I do 12 x 12 x 10 x 4= 5760

3 0
3 years ago
There are 4 red cars and 8 black cards in a bag. How is it likely that you will randomly draw a blue card
Verdich [7]

Answer:

C) Impossible

Step-by-step explanation:

Since there are no blue cards, the probability that you'd draw one is 0/12, which means that there is no chance you'll draw one.

4 0
3 years ago
Find me equation of the circle with Center at ( 3, - 2) and radius of 3
blondinia [14]

The equation of a circle with center (x_0,y_0) and radius r is

(x-x_0)^2+(y-y_0)^2=r^2

In your case,

x_0=3,\quad y_0=-2,\quad r=3

Plug these values into the generic formula and you'll get your equation.

5 0
3 years ago
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