Answer:
9:30 am
Step-by-step explanation:
We can make a chart and keep filling it in until we see the same time in both columns.
Bus A Bus B
7:00 7:00
7:30 7:50
8:00 8:40
8:30 9:30
9:00 10:20
9:30
Answer: 9:30 am
We can also use the least common multiple of 30 and 50.
We need to find the smallest number that is a multiple of both 30 and 50.
30 = 2 * 3 * 5
50 = 2 * 5^2
LCD = 2 * 3 * 5^2 = 150
The first time the buses will be at the depot together after 7:00 am is 150 minutes later. 150 minutes = 2 hours 30 minutes.
7:00 am + 2 hours and 30 minutes = 9:30 am
Answer: 9:30 am
64
80 80
thats how you havw to put it
Answer:
Step-by-step explanation:
There is missing information in the task: HD║FG !!!!!
∠HDE ≅ ∠FGE and ∠EHD ≅ ∠EFG
<u><em>ΔEHG ~ ΔEFG</em></u> (AAA theorem of similarity)
m∠F = 22°
m∠G = 89°
