Archean and Proterozonic which are both broken into early middle and late periods
Answer:
The correct answer is A.) during transcription
Explanation:
The pairing during DNA replication and transcription is a little bit different. During replication, A pairs with T, T with A, C with G, and G with C. In transcription T is replaced by U so when there is nucleotide adenine is present in the DNA sequence than uracil will be added against it as complementary nucleotide in mRNA during transcription.
So here 5'-GAT-3' nucleotide sequence is present in DNA and after transcription the nucleotide sequence will be 5'-CUA-5' because U is added against A during transcription. Therefore the correct answer is A.
The cytoskeleton of a cell allows the cell to be flexible. Our human skeletons allow <em>us </em>to be flexible.
<span>has a 50 percent chance of passing the mutated gene to each child. The chance that a child will not inherit the mutated gene is also 50 percent. </span>
The question is incomplete as it does not have the options which are:
A) n+1; n+1; n-1; n-1
B) n+1; n-1; n; n
C) n+1; n-1; n-1; n-1
D) n+1; n+1; n; n
Answer:
Option-1
Explanation:
The laws of inheritance were concluded from the result of Mendel's experiment which is based on the fact that gametes are formed. Later research suggested that gametes are formed by the process of meiosis which takes place in two phases and recombination is a characteristic of Meiosis.
If during anaphase I of meiosis I, the alleles fails to separate that is nondisjunction takes place at anaphase I, Then the resulting daughter cells will have unequal distribution of chromosomes.
One daughter cell will receive 1 extra copy of the chromosome while another daughter cell will receive 1 less chromosome therefore ploidy level will be n+1 and n-1.
During meiosis II, 2 more daughter cells will be formed with the same ploidy level therefore in last the meiosis will result in 2 (n+1) and 2 (n-1) cell.
Thus, Option-1 is the correct answer.
