Answer:
it should be 4:4
Explanation:
The p will stand for purple and the w will stand for white.
it would go like P | P
W | PW | PW
W | PW | PW
Answer:
The structure of their noses.
Explanation:
Catarrhines are distinguished from platyrrhines by several traits but the main distinctive feature between them, is the structure of their noses. This forms the basis of their names.
Platyrrhines are characterized by laterally-placed, rounded nostrils or flat-nosed while catarrhines have narrow, downward-facing nostrils or hooked-nosed.
Another distinguishing feature include their dental formulation which is 2.1.2.3 in catarrhines and 2.1.3.3 in platyrrhines.
The skull structure of catarrhines have frontal bone which make contact with the sphenoid bone unlike the platyrrhines.
Generally, catarrhines are much bigger in size than platyrrhines.
<span>Answer: A) Dark moths had a survival disadvantage in industrial Dorset.
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This question can be solely answered using the data you're given! The graph is broken down by place, and then moth type.
In forested Birmingham, the green bar for the light moth is much higher than the orange one for the dark moth. That means the light moth had a survival advantage (eliminating option D) and the dark moths had a survival disadvantage (eliminating option C).
In industrialized Dorset, the green bar for the light moth is much lower than the orange one for the dark moth. That means the light moths were at a survival disadvantage (eliminating option B). The dark moths were are a survival advantage, but option A says "disadvantage," which is clearly wrong! That makes A your answer.
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Lively is your answer.
Hope this helped! (:
Answer:
1/4
Explanation:
Cystic fibrosis is a recessive disorder and therefore, is expressed only in homozygous recessive genotype. Let's assume that the allele "c" is responsible for the disease in the homozygous state. Since the couple already has a child with cystic fibrosis (cc), they both are heterozygous carriers for the disease.
The genotype of male and female each is "Cc". A cross between Cc x Cc gives progeny in the following phenotype ratio=1/4 diseased: 1/2 normal carriers: 1/4 normal. Therefore, the probability of getting a diseased child for them is 1/4.
