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Iteru [2.4K]
3 years ago
13

CHOOSE, see the attachment Help me PLZZ. It's urgent. ​

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
4 0

Answer:

f)-2

thats the right answer

I am sure

hope it helps

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14. Solve the equation above for h​
Westkost [7]

Answer:

h=69

Step-by-step explanation:

H=VM2 +69=Y.......

5 0
3 years ago
Lane high school has 5 times as many students as park elementary. How many more students attend lane high school than park high
frosja888 [35]

Answer:

5 times as many

<em>BRAINLIEST, please!</em>

Step-by-step explanation:

I'd need more information about how many students there are at one of the schools. For example, if there are 200 students at Park Elementary, then there are 1000 at Lane High School since 200 x 5 = 1000. 1000 - 200 is 800, so there would be 800 more students at Lane High.

6 0
3 years ago
Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

Let \{c_n\} be the sequence of differences of \{b_n\},

c_n = b_{n+1} - b_n

and we see that this is a constant sequence, \{c_n\} = \{2, 2, 2, 2, \ldots\}. In other words, \{b_n\} is an arithmetic sequence with common difference between terms of 2. That is,

2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2

and we can solve for b_n in terms of b_1=4:

b_{n+1} = b_n + 2

b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2

b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2

and so on down to

b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)

We solve for a_n in the same way.

2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)

Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))

and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}

6 0
2 years ago
What is x equal to =
a_sh-v [17]

Answer:

Step-by-step explanation:

X= 3\frac{1}{3} or\frac{10}{3}

5 0
3 years ago
Help asap will give brainliest to whoever answer's correctly.
nydimaria [60]

Answer:

cant see the image

Step-by-step explanation:

8 0
3 years ago
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