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never [62]
3 years ago
8

Alexa is constructing a circle inscribed in a triangle. She has partially completed the construction as shown below.

Mathematics
1 answer:
Simora [160]3 years ago
8 0

Answer:

The next step is to use the compass to find the angle bisector for angle A.

Step-by-step explanation:

To construct a circle inscribed in a triangle we have following step of construction.

Step 1: To construct incenter.

Firstly, it is given that Alexa has partially completed the construction in which she constructs the angle bisector of B. Now, in order to construct incenter we need two angle bisectors and the intersection point of two angle bisector gives incenter.

Hence, her next step in the construction should be to draw one more angle bisector i.e use the compass to ind the angle bisector for angle A


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Point (-2,1) Doesn't fall on the line.

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9√5+√5
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&
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Write a list of steps that are needed to find the measure of angle B if angle A is 72 and angle C is 113 ( the figure is a trian
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Triangle has 3 angles, A, B, C. The total interior angle of a triangle is 180. 
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A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4
Vladimir79 [104]

Answer:

The time interval when V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

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Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

V_Q(t) \geq 60    between   0 \leq t \leq 4

The schematic free body graphical representation of the above illustration was attached in the file below and the point when V_Q(t) \geq 60  is at 4 is obtained in the parabolic curve.

So, V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

Taking the integral of the time interval in order to determine the distance; we have:

distance = \int\limits^{3.519}_{1.866} {V_Q(t)} \, dt

= \int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt

= By using the Scientific calculator notation;

distance = 106.109 m

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3 years ago
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2.66

Step-by-step explanation:

8 0
2 years ago
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