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dexar [7]
4 years ago
13

Use the slider to change the value of h. How does changing the value of h affect the vertex?

Mathematics
2 answers:
zlopas [31]4 years ago
8 0

If h= 3, the vertex shifts to -

3,0

If h= -5 the vertex shifts to -

-5,0

Hope this helps!

vodka [1.7K]4 years ago
3 0
It moves the line on the X axis to a different spot when moved

hope this helps <span />
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4 years ago
Roger is paid $50 to sell videos of a play to an audience after the play is performed.
emmasim [6.3K]
<h3>Answer: Choice A</h3>

The set of all even integers greater than or equal to 50 and less than or equal to 510

In other words, 0 \le E \le 510 where E is an even integer.

===========================================================

Explanation:

The domain is the set of allowed inputs, while the range is the set of allowed outputs. For now, let's focus on the domain.

In this case, the domain is the set of integers between 0 and 230. We're dealing with the set {0,1,2,..., 229, 230} to represent the possible number of people who bought the video.

Let's plug in the smallest item from the domain (v = 0).

E = 50+2v

E = 50+2*0

E = 50+0

E = 50

This matches with the fact Roger gets paid $50 even if he didn't sell anything. This is the flat up front fee he got.

Now let's plug in the largest value for v (230).

E = 50+2v

E = 50+2*230

E = 50+460

E = 510

This tells us that $510 is the most Roger can get from the audience of 230 people. This is assuming that each person buys only one copy.

So we can see that the range of E values spans from $0 to $510.

Furthermore, notice that 2 can be factored from 50+2v to get 2(25+v). This shows that the expression 50+2v is always even. Therefore, we must clarify that we're dealing with the set of even numbers between 0 and 510

In symbolic form, we'd say 0\le E \le 510 where E is an even integer.

In roster form, the range of possible E values is {0, 2, 4, ..., 506, 508, 510}.

7 0
3 years ago
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