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attashe74 [19]
3 years ago
12

Repeat Problem 1, except for an M/M/3 queue with mean interarrival time 1.25 minutes and mean service time 3 minutes at each of

the three servers. Hint: You might want to consider creating a computer program or spreadsheet, or use mmc.exe.
Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer:

Step-by-step explanation:

library('queueing')

i_mmmc <- NewInput.MMC(lambda=1/1.25, mu=1/3,c=3) #create input parameters

o_mmc <- QueueingModel(i_mmc) #Build the model

mmc_summ <- summary(o_mmc)

t(mmc_summ$el[c(1,2,3,10,7,11,8,12,9)])

## [,1]

## lambda 0.800000000

## mu 0.333333333

## c 3.000000000

## X 0.800000000

## P0 0.05617978

## L 4.98876404

## Lq 2.58876404

## W 6.23595506

## Wq 3.23595506

The command-line program from the Simio website(username and password in preface of book )provided a c++ executable file that calculates various M/M/c metrics.it is called using the command prompt,navigating to the directory of the mmc.exe file,and typing mmc followed by values of \lambda ,mu and c separated by space...

$ cd C:\Users\Ayush\Google Drive\Education\Masters\SPS\DATA 604\Simio_Student_Resources

$ mmc 0.8 0.33333333 3

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balandron [24]

Answer:

1 to 30 seconds

Step-by-step explanation:

3 seconds increases your speed from 32 to 35 miles per hour

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1 second = 1 mile

The function for the increase per mile is therefore:

f(x)= 1x

Where x is number of seconds travelled on the highway

The domain of a function are the possible input values for x. Since the speed limit on the highway is 65 miles, the input values for x cannot be more than 30 seconds(current speed is 35 miles per hour, 65-35=30)

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3 years ago
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Answer:

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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

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Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

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P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

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iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

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Westkost [7]

Answer:

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