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attashe74 [19]
3 years ago
12

Repeat Problem 1, except for an M/M/3 queue with mean interarrival time 1.25 minutes and mean service time 3 minutes at each of

the three servers. Hint: You might want to consider creating a computer program or spreadsheet, or use mmc.exe.
Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer:

Step-by-step explanation:

library('queueing')

i_mmmc <- NewInput.MMC(lambda=1/1.25, mu=1/3,c=3) #create input parameters

o_mmc <- QueueingModel(i_mmc) #Build the model

mmc_summ <- summary(o_mmc)

t(mmc_summ$el[c(1,2,3,10,7,11,8,12,9)])

## [,1]

## lambda 0.800000000

## mu 0.333333333

## c 3.000000000

## X 0.800000000

## P0 0.05617978

## L 4.98876404

## Lq 2.58876404

## W 6.23595506

## Wq 3.23595506

The command-line program from the Simio website(username and password in preface of book )provided a c++ executable file that calculates various M/M/c metrics.it is called using the command prompt,navigating to the directory of the mmc.exe file,and typing mmc followed by values of \lambda ,mu and c separated by space...

$ cd C:\Users\Ayush\Google Drive\Education\Masters\SPS\DATA 604\Simio_Student_Resources

$ mmc 0.8 0.33333333 3

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The number of entrees purchased in a single order at a Noodles &amp; Company restaurant has had an historical average of 1.7 ent
SOVA2 [1]

Answer:

t=\frac{2.1-1.7}{\frac{1.01}{\sqrt{48}}}=2.744    

p_v =P(t_{(47)}>2.744)=0.0043  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 1,7 entrees per order at 2% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=2.1 represent the mean

s=1.01 represent the sample standard deviation

n=48 sample size  

\mu_o =1.7 represent the value that we want to test

\alpha=0.02 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 1.7, the system of hypothesis would be:  

Null hypothesis:\mu \leq 1.7  

Alternative hypothesis:\mu > 1.7  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{2.1-1.7}{\frac{1.01}{\sqrt{48}}}=2.744    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=48-1=47  

Since is a one side test the p value would be:  

p_v =P(t_{(47)}>2.744)=0.0043  

Conclusion  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 1,7 entrees per order at 2% of signficance.  

4 0
3 years ago
Read 2 more answers
Pls send answer and show work pls
I am Lyosha [343]
For question 7, if we add all votes for tiger and eagle, we get

tiger = 14 + 13 + 8 + 5 = 40
eagle = 6 + 7 + 12 + 15 = 40

so choices A and B are wrong.
C is also wrong because fifth and sixth grade votes for eagle are 6 + 7 = 13 and the 5th and 6th grade votes for tiger are 14 + 13 = 27. clearly 5th + 6th like tiger more.

D is the answer for question 7

question 8

rolling a cube does not affect the other cube so it is all independent probability.
cube: 1 2 3 4 5 6
3 even numbers and 3 odd numbers

so probability of rolling an even number is

1/6 + 1/6 + 1/6 = 3/6 = 1/2

multiplying by total number of rolls, she will get even numberss

300 * 1/2 = 150

about 150 time.
so half of the time, Cassie will roll and even number about half the number of rolls. never exactly since this is all probability. more likely for it to be around 150 times than exactly 150 time.

choice C is answer for question 8
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d1i1m1o1n [39]

Answer:

Step-by-step explanation:

-6 - (-9)

1) Remove parentheses

-6 + 9

2) Simplify

3

See attachted image for rules of positive and negative integers.

Source: YourDictionary

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alina1380 [7]

Answer:

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Step-by-step explanation:

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