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ki77a [65]
2 years ago
9

Solve. 6−3x=3(8−x) 4 all real numbers −4 no solutions

Mathematics
1 answer:
klio [65]2 years ago
8 0
Yea no solution is your answer
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Help................​
guapka [62]

Answer:

6.2 a QR

6.2 b 180

6.3 a By aas axiom

5 0
2 years ago
Square root of -1? PLEASE HELP
kolezko [41]

My understanding it would be letter ( i )  because it is imaginary.  

7 0
2 years ago
What is the equation of the line? Graph of a line in the coordinate plane through the origin and the point begin ordered pair 1
Margarita [4]

Here the line passes through (0,0) and (1,3).

First we need to find the slope , and for that we need to use the following formula

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

On substituting the values from the point, we will get

m=\frac{3-0}{1-0}=3

Now we will use slope intercept form, which is

y = mx+ b

Where m is the slope and b is the y intercept

And on substituting the values of x and y from the point (1,3) and slope, m = 3, we will get

3 = 3(1)+b

3=3+b

b =0

Substituting the values of m and b in the slope intercept form, we will get

y= 3x

4 0
3 years ago
Read 2 more answers
Without multiplying, order the following products from least to greatest. 23* 2/2 23* 1/4 23* 13/5
Romashka-Z-Leto [24]
Answer:

From least to greatest

23* 1/4, 23* 2/2, 23* 13/5

Explanation

In order to do this without multiplication, place the fractions in ascending order.

The denominators of these fractions have 20 as a common multiple.

2/2 • 10 = 20/20

1/4 • 5 = 5/20

13/5 • 4 = 52/20

From this it logically follows that the fractions in ascending order are:

1/4, 2/2, 13/5

Therefore the products in ascending order are:

23* 1/4, 23* 2/2, 23* 13/5



7 0
3 years ago
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
2 years ago
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