What is the volume of a sphere if it's greater circle has an area of 9pi cm?

1 answer:

5 0

Area of circle = π · r²
   9 π = π · r²
   9 = r²
   3 = r

Volume of sphere = (4/3)π · r³
         = (4/3)π · (3)³
   = 4π · 3²
   = 4π · 9
   = 36π

Answer: the volume of the sphere is 36π

You might be interested in

In 2001, the United States' oil consumption was 7,297.4 millions of barrels, while Japan's was 1,979.4 millions of barrels. How

AleksAgata [21]

The answer would be 5,318,000 more barrels were consumed by the U.S than Japan

5 0

2 years ago

Read 2 more answers

To hang a 9-ft hammock from a tree, you first tie one end to the trunk of the tree. When the hammock is tied on one end, it make

Delicious77 [7]

Hi mom mom I will call you

8 0

2 years ago

An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then

Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

$\angle Q=110^\circ$

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

$q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km$

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

$=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)$

(b)Flight Direction of Y

Using Law of Sines

$\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)$