Answer:At the time of rental, an authorized hold will be secured on your credit/debit card provided to cover the estimated rental charges plus an additional $200.00 to cover additional charges that may be incurred.
Step-by-step explanation:
Step-by-step explanation:
45+90+x=180
135+x=180
x=180-135
x=45
Answer:
Answer: The value of X is 28
Answer:
Janies' monthly pocket money is $180.
Step-by-step explanation:
Janies' adjusted monthly pocket money:
Initial pocket money = $150
Ratio of new pocket money = 6:5
Let his new pocket money be represented by x,
x:$150 = 6:5
$150 x 6 = x (5)
$900 = 5x
x = 
x = $180
Therefore, Janies' monthly pocket money is $180.
We want to find one-half of the reciprocal of 7/sqrt(98). Let's write down an expression for this:

We can rewrite 98 into 


The square root of 49 is 7



This should be your answer. Let me know if you need any clarifications, thanks!