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Temka [501]
3 years ago
13

What is the equation of the line? I’LL GIVE BRAINLIEST

Mathematics
2 answers:
Liula [17]3 years ago
6 0

Answer:

y=2x-4

Step-by-step explanation:

Goryan [66]3 years ago
4 0

Answer:

An equation is written in the form y=mx+b. “m” is the slope and “b” is the y-intercept. In the graph we see that the line crosses the y-axis at 2. So the y-intercept in 2. To find the slope, you use the distance formula. The distance formula is Y2-Y1/X2-X1. Take two points and plug them into this equation. I will use (0,2) and (2,3).

2-3/0-2

-1/-2

1/2

The slope of the line is 1/2. So, the equation of the line is y=1/2x+2.

:)

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Choose the equation that represents the graph.
Sergeu [11.5K]

Answer:

y=-2x-4

Step-by-step explanation:

y=mx+b

count the slope (-2/1)

find the y-intercept(0,-4)

write it out (-2/-1)x-4

simplify (-2x-4)

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Find the x-intercept of the line:
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What is the maximum number of consecutive positive integers that can be added together to create a sum less than 400?
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| 3 - 10 | - ( 12 ÷ 4 + 2 )
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Answer: 12

pls thank  me and branliet

Step-by-step explanation:

7 0
3 years ago
Five individuals from an animal population thought to be near extinction in a certain region have been caught, tagged, and relea
Talja [164]

Answer:

a) For this case the random variable X follows a hypergometric distribution.

b) E(X)= n\frac{M}{N}=10 \frac{5}{25}=2

Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1

c) P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565

d) P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474

Step-by-step explanation:

The hypergometric distribution is a discrete probability distribution that its useful when we have more than two distinguishable groups in a sample and the probability mass function is given by:

P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes

The expected value and variance for this distribution are given by:

E(X)= n\frac{M}{N}

Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}

a. What is the distribution of X?

For this case the random variable X follows a hypergometric distribution.

b. Compute the values for E(X) and Var(X)

For this case n=10, M=5, N=25, so then we can replace into the formulas like this:

E(X)= n\frac{M}{N}=10 \frac{5}{25}=2

Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1

c. What is the probability that none of the animals in the second sample are tagged?

So for this case we want this probability:

P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565

d. What is the probability that all of the animals in the second sample are tagged?

So for this case we want this probability:

P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474

4 0
3 years ago
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