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Sliva [168]
2 years ago
9

How can you represent a proportional relationship using an equation?

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
6 0

Answer:

The equation for the proportional relationship is y = 2.8x.

If the relationship between two quantities is a proportional relationship, this relationship can be represented by the graph of a straight line through the origin with a slope equal to the unit rate.

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A movie rental kiosk charges a $25 membership fee and $3 per movie. An online movie service charges a $20 membership fee and $4
mylen [45]
25+3m=20+4m 
25=20+m
5=m 

7 0
3 years ago
write each ratio statement as a fraction and reduce to lowest terms if possible.(i)18 to 24 (ii)5 to 15 (iii)14:42 (iv) 15 cents
ArbitrLikvidat [17]

Answer:

i) 3/4

ii) 1/3

iii) 1/3

iv) 5/6 cents

Step-by-step explanation:

Any ratio can be written as a fraction.

For example 3:4 can be writen as 3/4 or 14:42 as 14/42.

After you convert them to fractions you then simplify them by finding their highest common factor (HCF) and then divide both numerator and denominator by the HCF. When you cant simplify the fraction anymore, that is the fraction in its lowest terms.

4 0
2 years ago
How many faces does the solid made from the net below have? A. 7B. 8C. 12D. 18
Kruka [31]

Answer:

B. 8

Explanation:

The figure forms a septagon.

The hexagons form the base, and the rectangles attached to them form the sides.

Therefore, in total the solid has two hexagons as sides and 6 rectangles connecting the hexagon to the base hexagon. Hence, in total the solid has

2 + 6 = 8 faces.

7 0
1 year ago
Find the scale factor of the smaller figure to the larger figure
3241004551 [841]
(smaller length measure) to (larger length measure)
3 to 9 or 6 to 18
reduces to 1 to 3 or \frac{1}{3}
5 0
2 years ago
Read 2 more answers
Find the derivative of F(x)=-x^4+4x^3+ 70 for 0<=x<=3
timofeeve [1]

Answer:

  -4x^3 +12x^2 for 0 < x < 3

Step-by-step explanation:

The power rule is appropriate:

  (d/dx)x^n = n·x^(n-1)

This is applied to each of the terms.

  F'(x) = -(4·x^3) +4(3x^2) +0

  F'(x) = -4x^3 +12x^2 . . . . for 0 < x < 3

__

The derivative is not defined at the endpoints of the interval, so F'(x) is only defined on (0, 3), not [0, 3].

8 0
3 years ago
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