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MatroZZZ [7]
3 years ago
12

Sofia bought 12 pens for $0.59 each. she paid with a $10 bill. how much change will she receive?

Mathematics
1 answer:
Sidana [21]3 years ago
8 0
The 12 pens would cost $7.08. If you paid with a $10 dollar bill, she would get $2.92 back.
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8ft=how many yards and feet 68in=how many ft and in 3,520y=how many miles
Nataly_w [17]
8ft = 2yrds and 2 feet
68in= 5ft and 8in
I don't know the last one XD
3 0
3 years ago
What is the classification for this polynomial?
Mariana [72]

Answer:

Trinomial

Step-by-step explanation:

This is because there are three terms involved in the equation.

One of them is -7ab^4. Another is 4c^3. The third one is 25.

4 0
3 years ago
Does the equation 6x + 35 = -6x - 35 have no, one, or infinite solutions?
fenix001 [56]

Answer:

The equation has one solution.

Step-by-step explanation:

6x + 35 = -6x - 35

subtract 6x from both sides of the equation

35 = -35 - 12x

add 35 to both sides of the equation

70 = -12x

divide -12x on both sides of the equation

x = 5.833333333

6 0
2 years ago
Consider the function f(x)=xln(x). Let Tn be the nth degree Taylor approximation of f(2) about x=1. Find: T1, T2, T3. find |R3|
Fynjy0 [20]

Answer:

R3 <= 0.083

Step-by-step explanation:

f(x)=xlnx,

The derivatives are as follows:

f'(x)=1+lnx,

f"(x)=1/x,

f"'(x)=-1/x²

f^(4)(x)=2/x³

Simialrly;

f(1) = 0,

f'(1) = 1,

f"(1) = 1,

f"'(1) = -1,

f^(4)(1) = 2

As such;

T1 = f(1) + f'(1)(x-1)

T1 = 0+1(x-1)

T1 = x - 1

T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2

T2 = 0+1(x-1)+1(x-1)^2

T2 = x-1+(x²-2x+1)/2

T2 = x²/2 - 1/2

T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3

T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3

T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)

Thus, T1(2) = 2 - 1

T1(2) = 1

T2 (2) = 2²/2 - 1/2

T2 (2) = 3/2

T2 (2) = 1.5

T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)

T3(2) = 4/3

T3(2) = 1.333

Since;

f(2) = 2 × ln(2)

f(2) = 2×0.693147 =

f(2) = 1.386294

Since;

f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).

Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,

Since;

f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2

Finally;

R3 <= |2/(4!)(2-1)^4|

R3 <= | 2 / 24× 1 |

R3 <= 1/12

R3 <= 0.083

5 0
3 years ago
WILL GIVE BRAINLIEST if thorough steps are provided!
leonid [27]

Answer: 106.5 I believe

Step-by-step explanation:it’s gonna be 6 to the third power minis three over x=2

4 0
2 years ago
Read 2 more answers
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