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3 years ago

8

Developmental norms are used as a benchmark to determine where one should be developmentally. Please select the best answer from

the choices provided T F

2 answers:

Sati [7]3 years ago

8 0

Answer:

True

Step-by-step explanation:

ed 2020. I went back to check the answer so 100% right.

Pani-rosa [81]3 years ago

7 0

Answer:

tru

Step-by-step explanation:

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The dot is located at -1.13

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What is the slope of the line shown below?<br><br> (9, 1) and (-3, -7

Dima020 [189]

Answer:

The slope is 4

Step-by-step explanation:

I think it's right

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3 years ago

A land developer is splitting up 1.19 hectares of land to form 9 identical properties. To the nearest tenth of a hectare, what s

OlgaM077 [116]

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4 years ago

What is the slope of the line y - 5 = -4(x - 8)?

galben [10]

Answer:

-4

Step-by-step explanation:

This looks like point-slope form, which I find personally hideous. Let's change it to slope-intercept form to ease my conscience. (remember that slope-intercept form is y=mx+b, where m=slope and b=y-intercept!)

y - 5 = -4(x-8)

y - 5 = -4x + 32

y = -4x + 37

It's in slope-intercept form now! And -4 looks to be our m.

<u>So the slope is -4.</u>

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4 years ago

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Find the distance and midpoint of a segment with the following endpoints: (5,-1) and (-9,-1)

Likurg_2 [28]

Answer:

$d = 14$

$(-2,-1)$

General Formulas and Concepts:

Order of Operations: BPEMDAS
Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

<u>Step 1: Define</u>

(5, -1)

(-9, -1)

<u>Step 2: Find distance </u><em><u>d</u></em>

Substitute: $d = \sqrt{(-9-5)^2+(-1-(-1))^2}$
Simplify: $d = \sqrt{(-9-5)^2+(-1+1)^2}$
Subtract/Add: $d = \sqrt{(-14)^2+(0)^2}$
Evaluate: $d = \sqrt{196}$
Evaluate: $d = \14$

<u>Step 3: Find Midpoint</u>

Substitute: $(\frac{5-9}{2},\frac{-1-1}{2})$
Subtract: $(\frac{-4}{2},\frac{-2}{2})$
Divide: $(-2,-1)$

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3 years ago