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gizmo_the_mogwai [7]
2 years ago
15

Consider the rectangular prism. What is the surface area of the rectangular prism?

Mathematics
2 answers:
bagirrra123 [75]2 years ago
7 0
240 in 2 hope this helps
ankoles [38]2 years ago
4 0

Answer:The answer would be 240in 2

Step-by-step explanation:10 times 6 is 60 times 4 is 240 I hope this helps.

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What is the answer to -7=-12 (-2)+B please help!
insens350 [35]
I would solve it for B, but that's just what I think. So you would do -12 time -2 which is 24, then subtract 24 from both sides so that you would get B=-31
8 0
3 years ago
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Which is an equation of the line that passes through (2, -5) and (6, 3)?
Tresset [83]

Answer: y = 2x - 9

Step-by-step explanation:

I graphed it and did the work in my head-

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2 years ago
Trisha is going to make a border of icing around a circular cake with a diameter of 8 inches which of the following represents t
nadya68 [22]

Answer:

B. 25.12

Step-by-step explanation:

We are simply finding the perimeter of the cake.

Perimeter: π × diameter

Perimeter: 3.14 × 8

Perimeter: 25.12 inches

4 0
3 years ago
How much fencing will John need? Use 22/7 for x.
Serjik [45]

Well 22/7 is 3.14 and so on but since there is a little more than 3 you need to make sure he covers up all the fencing places... SO John will need 4 fences

4 0
3 years ago
The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and
NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120

Let's find h with the quadratic formula:

\fbox {Quadratic formula:}  \frac{-b\pm\sqrt{b^2-4ac}}{2a}

h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation  

\fbox {Pythagorean equation:} <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>

The base and the height are our legs. We will use "H" for the hypotenuse

H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17

H = 17

If we decrease the base and the height by 2 centimeters, we have  

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3

H' \approx 14.3

So, the hypotenuse decreases H - H' \approx 17 - 14.3 = 2.7

3 0
3 years ago
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