Answer:
The valves perform above expectations.
Step-by-step explanation:
We are given the following information in the question:
Population mean, μ = 7.6 pounds per square inch
Sample size, n = 140
Sample mean,
= 7.8 pounds per square inch
Population standard deviation = 1.0 pounds per square inch
Level of significance = 0.05
We design the null and alternate hypothesis:
: μ = 7.6 pounds per square inch
: μ > 7.6 pounds per square inch
Formula:



Now, we are performing a one tail test with level of significance of 0.05, we calculate the critical value of z with the help of standard normal distribution table.
Thus,
= 1.645
Result:
Since, 
is rejected.
Thus, we accept the alternate hypothesis.
Hence, the valve perform above expectations.