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muminat
3 years ago
14

What proves m ∆ADB and ∆ADC are congruent.

Mathematics
1 answer:
AURORKA [14]3 years ago
6 0

Answer: They're the same angles/measurements.

Step-by-step explanation: Look closely at both the angles. If you measure them, they will be the same because both angles look the same, but ΔADC's side is flipped.

Let me know if you have any questions.

~ Lily, from Brainly.

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A rectangular page is to contain 24 sq. in. of print. The margins at the top and bottom of the page are each 1.5 inches. The mar
suter [353]

Answer:

Dimensions of page should be width of 6 inches and height of 9 inches

Step-by-step explanation:

Let x be the width of the printed part in inches

Let y be height of the printed part in inches.

Thus, Area of printed part; A = xy

And area of printed part is given as 24.

Thus, xy = 24

Making y the subject, we have;

y = 24/x

Now, the question says the top and bottom margins are 1.5 inches.

Thus, width of page = x + 1 + 1 = x + 2

And also the margins on each side are both 1m in length, thus the height of page will be:

y + 1.5 + 1.5 = y + 3

So area of page will now be;

A = (x + 2)•(y+3)

From earlier, we got y = 24/x

Thus,plugging this into area of page, we have;

A = (x + 2)•((24/x)+3)

A = 24 + 3x + 48/x + 6

A = 30 + 3x + 48/x

For us to find the minimum dimensions, we have to find the derivative of A and equate to zero

Thus,

dA/dx = 3 - 48/x²

Thus, dA/dx = 0 will be

3 - 48/x² = 0

Multiply through by x²:

3x² - 48 = 0

Thus,

3x² = 48

x² = 48/3

x = √16

x = 4 inches

Plugging this into y = 24/x,we have;

y = 24/4 = 6 inches

We want dimensions of page at x = 4 and y = 6.

From earlier, width of page = x + 2.

Thus,width = 4 + 2 = 6 inches

Height = y + 3 = 6 + 3 = 9 inches

So dimensions of page should be width of 6 inches and height of 9 inches

4 0
3 years ago
*NO 194 39% 13:08 Pilih jawaban yang paling tepat Segitiga PQR dan segitiga XYZ 5 poin merupakan dua segitiga yang kongruen. Bes
Illusion [34]

Answer:

Option d. PQ = YZ

Step-by-step explanation:

<u><em>The question in English is</em></u>

Choose the most appropriate answer. The PQR triangle and the XYZ triangle are two congruent triangles. The angle P = the angle Y and PR = YX. Side pairs of the same length are ... a. PQ = XZ b. QR = YZ c. QR = XY d. PQ = YZ

we know that

If two triangles are congruent, then its corresponding sides and its corresponding angles are congruent

Corresponding sides are named using pairs of letters in the same position on either side of the congruence statement

so

we have that

m\angle P=m\angle Y

PR=YX

so

Triangle PQR is congruent with Triangle YZX

That means

<em><u>Corresponding angles</u></em>

m\angle P=m\angle Y

m\angle Q=m\angle Z

m\angle R=m\angle X

<u><em>Corresponding sides</em></u>

PQ=YZ\\QR=ZX\\PR=YX

8 0
3 years ago
How do i solve this inequality? -2|3m|+3&lt;-51
9966 [12]

Answer:

m >9  or      m < -9

Step-by-step explanation:

-2|3m|+3<-51

Subtract 3 from each side

-2|3m|+3-3<-51-3

-2|3m|<-54

Divide each side by -2, remembering to flip the inequality

-2|3m|/ -2>-54/-2

|3m|> 27

To get rid of the absolute values, we separate into two inequalities, one as written and one negative, remembering to flip the inequality

3m >27  or     3m <-27

Divide by 3 on each side

3m/3 >27/3  or     3m/3 <-27/3

m >9  or      m < -9

4 0
3 years ago
How to do this please Explain Thank you
Maurinko [17]

Answer:

x = 47

Step-by-step explanation:

There Are Many Methods In Which You Can Do It.

X = 47 ( Alternate Angles)   <em>//Alternate angles are angles that are in opposite  positions relative to a transversal intersecting two lines.</em>

<em />

6 0
3 years ago
Read 2 more answers
Solve this inequality for y.<br> - 3y + 12 26
Gennadij [26K]

Answer:

-2^5

Step-by-step explanation:

hope it helped. im not sure..

4 0
3 years ago
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