All categories

3 years ago

What do i put for y and x , need help asap!!!

Mathematics

1 answer:

pogonyaev3 years ago

8 0

Pick a point on the line and then what ever number is directly across from that point put in the y section. Whatever is directly under or over that point put it in the x
For ex- y = -1 and x = -3

You might be interested in

Observe the sequence below 37,41,45,49

lawyer [7]

Answer:

a n = 4 n + 33

Step-by-step explanation:

n = number of jumps after the 0 term of '33'

aka: add 4 to the previous number

5 0

2 years ago

What is equivalent to n^-10/n^2

denis-greek [22]

Answer:

1/n^12 or n^-12

Step-by-step explanation:

=n^-10 / n^2

=1/n^10 / n^2

=(1/n^10) *(1/n^2)

=1/n^12

7 0

2 years ago

Kelly has 4 times as many songs on her music player as Lou

jeka57 [31]

Answer:4 times x

4(x)

Step-by-step explanation:

4 times as many songs on Lou's music player

Lou's music player is x

7 0

3 years ago

Please help with this Math Question...

Nataly [62]

Answer: A

<u>Step-by-step explanation:</u>

f(x) = x³ + 4x² + 7x + 6

possible rational roots are ±{1, 2, 3, 6}

Try x = -2

-2 | 1 4 7 6

1 2 3 0 ← remainder is 0 so x = -2 is a root ⇒ (x + 2) = 0

The factored polynomial x² + 2x + 3 = 0 is not factorable so use the quadratic formula to find the roots.

a=1, b=2, c=3

$x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\dfrac{-(2)\pm\sqrt{(2)^2-4(1)(3)} }{2(1)}$

$x=\dfrac{-2\pm\sqrt{4-12} }{2}$

$x=\dfrac{-2\pm\sqrt{-8} }{2}$

$x=\dfrac{-2\pm2i\sqrt{2}}{2}$

$x = -1 \pm i\sqrt{2}$

$x = -1 + i\sqrt{2}$ $x = -1 - i\sqrt{2}$

$x - (-1 + i\sqrt{2})=0$ $x - (-1 - i\sqrt{2})=0$

The factors are:

$(x - 2)[x - (-1 + i\sqrt{2})][x - (-1 - i\sqrt{2})]$

5 0

2 years ago

Brent and Lance leave a park on bicycles traveling at constant rates in opposite directions. After 2.5 hours, they are 85 miles

stealth61 [152]

Answer:

18 mph so B is correct 16+2= 18

8 0

2 years ago

Read 2 more answers