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rjkz [21]
3 years ago
9

Which Venn diagram has shading that represents the given set? A^cnB

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0

Answer:

b

Step-by-step explanation:

You might be interested in
Please help me on this quick!! Thanks and please show work.
FinnZ [79.3K]
The two parallel bases b1 and b2 are
b1 = 12
b2 = 9
the order of which base you pick doesn't matter

The height is h = 10 and it's perpendicular to each base.

The area is...

A = (1/2)*h*(b1+b2)
A = (1/2)*10*(12+9)
A = (1/2)*10*(21)
A = 5*21
A = 105

Final Answer: B) 105 square centimeters
8 0
3 years ago
I need help please.
IgorC [24]
The answer a I believe so.
8 0
3 years ago
True or false: A triangle can be made by segments that are 15.9 cm, 10 cm and 25.9 cm.
Gala2k [10]

Answer:

false

Step-by-step explanation:25.9cm is too big to connect to 15.9cm and 10 cm

4 0
2 years ago
The bar of the square pyramid shown has and area of 576 units. If the slant height of the pyramid is 29 units, what is the heigh
Aloiza [94]

Answer:

\sqrt{697}

Step-by-step explanation:

If the base of the square pyramid has an area of 576 units, then the side length must have a length of \sqrt{576}=24. 24/2=12, and using the pythagorean theorem you can find that the height of the pyramid is \sqrt{29^2-12^2}=\sqrt{697}. Hope this helps!

8 0
3 years ago
What is the sum of a 12-term arithmetic sequence where the last term is 13 and the common difference is -10?
Y_Kistochka [10]
\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=12\\
d=-10\\
a_{12}=13
\end{cases}
\\\\\\
a_{12}=a_1+(12-1)d\implies 13=a_1+(12-1)(-10)
\\\\\\
13=a_1-110\implies \boxed{123=a_1}

\bf \\\\
-------------------------------\\\\
\textit{sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n}{2}(a_1+a_n)\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
a_n=\textit{value of the }n^{th}\ term\\
------------\\
n=12\\
a_1=123\\
a_{12}=13
\end{cases}
\\\\\\
S_{12}=\cfrac{12}{2}(a_1+a_{12})\implies S_{12}=\cfrac{12}{2}(123+13)

and surely you know how much that is.
6 0
3 years ago
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