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3 years ago

How do i draw two number lines that show 0.20 and 1/5 are equivalent?

1 answer:

6 0

The frist line may be one with the numbers 0, 1 and 2 and 10 divisions (marks at equal distance) between each integer. Each division will be equal to 0.1 units and then you can mark the second division from the zero point to the right as the 0.20 mark.

The other line must have the same integers, 0 , 1 and 2 placed in identical form as the first line. Then
   - draw an inclined straight line since the point zero,
   - mark 5 points in the inclined lined equally spaced over the line.
   - draw a sttraight line from the 5th point to the point with the mar 1 over the base number line.
   - draw a parallel line to the previous one passing trhough the second point of the inclined line and mark the point where this parallel touchs the base number line. This point shall be at the same distance from zero than the 0.2 mark was in the first number line, meaning that 0.2 and 1/5 are equivalent.

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3 years ago

Read 2 more answers

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are without replacement.

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago

Last HW Mr Thompson! Please Help!

TiliK225 [7]

Answer:

B, D, D, B, C

Step-by-step explanation:

1) The part of the equation that tells us the graph would open downward would be B, the negative coefficient of $x^{2}$ .

We know this because, if we reorganize the equation into the standard form y = mx + b, we get y = -(x²) + 1. This means that for any value we substitute for x, y will always be negative. The answer is B.

2) To find the zeroes of this function, we just have to see which answer makes the function, well, zero.

We have the equation y = (-16t - 2) (t - 1)

We set the equation equal to zero like this:

0 = (-16t - 2) (t - 1)

We also know that anything multiplied by zero will equal zero, so:

0 = (-16t - 2) and 0 = (t - 1)

Now we just solve for t in both equations:

0 = -16t - 2

-16t = 2

t = 2/-16 or -1/8

0 = t - 1

t = 1

So our answer will be D.

3) This time, we are given the same equation but the variable t represents time and y represents the height.

The zeroes are when y = 0, so the zeroes (which are 1 and -1/8 from the last problem) mean that the height is also at zero (which is the ground).

Furthermore, time cannot be negative, so the correct answer choice would be D.

4) We are given the same equation and story problem, but instead we are asked to find the height when the ball was thrown. In other words, we need to find the y-intercept.

The y-intercept is when t = 0, so:

y = (-16t - 2) (t - 1)

y = (-16(0) - 2) (0 - 1)

y = (-2) (-1)

y = 2

So, the correct answer is B, 2 feet.

5) This problem is a simple theoretical question. We know that the constant c will represent the vertical translation or y-intercept, so the correct answer is C.

8 0

3 years ago