Explanation:
According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.
As the given reaction is as follows.
(a) When increase the temperature of the reactants or system then equilibrium will shift in forward direction where there is less temperature. It is possible for an endothermic reaction.
Thus, formation of 
will increase.
- (b) When we decrease the volume (at constant temperature) of given reaction mixture then it implies that there will be increase in pressure of the system. So, equilibrium will shift in a direction where there will be decrease in composition of gaseous phase. That is, in the backward direction reaction will shift.
Hence, formation of will decrease with decrease in volume.
- When we increase the mount of
then equilibrium will shift in the direction of decrease in concentration that is, in the forward direction.
Thus, we can conclude that formation of will increase then.
Energy given by carbohydrates present in one cup =
= 128 kcal
Energy given by proteins present in one cup = 
Energy given by fat in one cup = 
Total energy in one cup of cereal box = 128 kcal + 16 kcal + 18 kcal = 162 kcal
Energy present in two cups = [tex] 2 cups * \frac{162 kcal}{1 cup} *
= 324 kcal
Strontium element has a mass number of 88 and contains 50 neutrons in the atom.
Given that;
Mass number of element X = 88
Number of Neutrons in element X = 50
we know the concept that Mass number is represent as total number of Neutrons and proton present in Nucleus
So, Mass number of element X = Number of Neutrons in element X + Number of Protons in element X
Thus, 88 = 50 + Number of Protons in element X
Number of Protons in element X = 38
As, Number of proton = Atomic number
So, Atomic number of element X = 38
Hence Unknown Element X is Strontium
To know more about Strontium element visit here ; brainly.com/question/19298437?referrer=searchResults
#SPJ4
Answer:
In all the problems below, the pressure and the amount of gas are held constant. Problem #1: Calculate the decrease in temperature (in Celsius) when 2.00 L at 21.0 °C is compressed to 1.00 L. Converting 147.0 K to Celsius, we find -126.0 °C, for a total decrease of 147.0 °C, from 21.0 °C to -126.0 °C.
