Given:
Q = 45.5 J, amount of heat absorbed
ΔT = 28.5 - 21.1 = 7.4 °C = 7.4 K, temperature change
c = 0.82 J/(g-°C), specific heat of CaCO₃.
Le m = the mass of the sample (g).
Then
Q = mcΔT
(45.5 J) = (m g)*(0.82 J/(g-°C))*(7.4 °C)
m = 45.5/(0.82*7.4) = 7.4984 g
Answer: 7.5 g (nearest tenth)
Answer:
0.385 J/g°C
Explanation:
Using the following formula, the specific heat of an elemental substance can be calculated:
Q = m × c × ∆T
Where;
Q = quantity of heat (J)
m = mass (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
Based on the given information, Q = 1375J, m = 50g, initial temperature = 22.8°C, final temperature = 94.2°C, c =?
Q = m × c × ∆T
1375 = 50 × c × (94.2 - 22.8°C)
1375 = 50 × c × 71.4
1375 = 3570c
c = 1375/3570
c = 0.3851
c = 0.385 J/g°C
Answer:
Risk management
Explanation:
Risk communication is exchange of the advice, real-time information and the opinions between the experts and the people which are facing threats to their economic, health, or well-being.
Risk assessment is overall process where the hazards and the risk factors which have potential to cause the harm is identified.
Risk perception is subjective judgement which people/ experts make about characteristics and the severity of the risk.
Risk management is evaluation, identification and prioritization of the risks followed by the coordinated and the economical application of the resources to monitor, minimize and control probability of the unfortunate events.
Thus, Option D is correct because in risk management, a Quantitative Solution is given to decrease risk level like to recycle the plastic.
Answer: In this compound, phosphorous and oxygen act together as one charged particle, which is connected to magnesium, the other charged particle.
Explanation:
