Answer:
a
Explanation:
The formation of ion occurs when an atom that is said to be neutral gains or losses electrons.
At the time it gains electrons, it is regarded that a negative ion (anion) is formed.
When it loses electron, it is regarded that a positive ion (cation) is formed.
Atomic number = No of protons and electrons occurring in a neutral atom.
Given that:
Protons = 14
electron = 18
Net Charge = no of proton - no of electron
= 14 - 18
= -4
Mass number = 14 + 15 = 29
So, the chemical symbol = 
For ion with
27 proton, 32 neutrons and 25 electrons
Net charge = 27 - 25
= +2
Mass number = 27 + 32 = 59
Thus, the chemical symbol = 
Answer:
The percent yield of this reaction is 42.1 % (option B)
Explanation:
Step 1: Data given
Theoretical yield of beryllium chloride = 10.7 grams
actual yield of beryllium chloride = 4.5 grams
Step 2: Calculate the percent yield for this reaction
Percent yield = (actual yield / theoretical yield) * 100%
Percent yield = (4.5 grams / 10.7 grams ) * 100 %
Percent yield = 42.1 %
The percent yield of this reaction is 42.1 % (option B)
We are told that the concentration of sodium hypochlorite is 4.0% (w/v). To calculate the molarity of the sodium hypochlorite solution, let us consider a sample volume of 0.1 liter. Since we are given a w/v (Percent of weight of solution in the total volume of solution) value, it means that there are 4 <span>grams of sodium hypochlorite per 100 mL of solution (0.1 liter). Molarity is measured in moles per liter. So we'll just convert the given 4 grams to moles using the molar mass.
</span><span>
4 grams</span>sodium hypochlorite * (1 mol sodium hypochlorite/ 74.44 g sodium hypochlorite) = 0.054 moles sodium hypochlorite
So we have 0.054 moles sodium hypochlorite / 0.1 L solution
<span>
Thus the molarity is 0.53 mol/L or just 0.53 M.
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Answer:
The answer to your question is Cr₂O₃ + 3Mg ⇒ 2Cr + 3MgO
Explanation:
Data
Unbalanced chemical reaction
Cr₂O₃ + Mg ⇒ Cr + MgO
Reactants Elements Products
2 Cr 1
3 O 1
1 Mg 1
Balanced chemical reaction
Cr₂O₃ + 3Mg ⇒ 2Cr + 3MgO
Reactants Elements Products
2 Cr 2
3 O 3
3 Mg 3
Now the reaction is balanced
