1220 Subtracting the lower boundary of 1492 grams from the mean of 3234 gives you 1742 grams below the mean. Dividing 1742 by the standard deviation of 871 gives you 2 standard deviations below the curve. Now doing the same with the upper limit of 4976 grams also gives you 2 standard deviations above the mean (4976-3234)/871 = 2 So you now look for what percentage of the population lies within 2 standard deviations of the mean. Standard lookup tables will indicate that 95.4499736% of the population will be within 2Ď of the mean. So multiply 1278 by 0.954499736 giving 1219.851. Then round to the nearest whole number and you have an estimated 1220 babies that weigh between 1492 grams and 4976 grams.

6 0

4 years ago

Read 2 more answers

Logariths, please help

Valentin [98]

Answer:

{ - 2 , 8 }

Step-by-step explanation:

$log_{4}$ ( x² - 6x ) = 2

4² = ( x² - 6x )

x² - 6x - 16 = 0

- 6 = - 8 + 2

- 16 = - 8 * 2

( x - 8 )( x + 2 ) = 0 ⇒ $x_{1}$ = - 2 , $x_{2}$ = 8

{ - 2 , 8 }

3 0

2 years ago

How many

AVprozaik [17]

Answer:the answer is

Step-by-step explanation:

First convert 7 1/2 to an improper fraction

15/2 ÷ 3/4

Division of fractions hold the first fraction replaces ÷ with x then flip the second fraction

15/2 x 4/3

Multiply the tops 15x4 =60

Over the bottoms multiplied together 2x3=6

60/6=10

10 people can be served that should help

6 0

3 years ago

The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.

melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

The common ratio is: $\mathbf{r = \frac{a + 5d}{a + d}}$
The general term of the GP is: $\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$