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SSSSS [86.1K]
3 years ago
8

4. Mr Vidal puts (c) gallons of gasoline in my car at a price of $1.98 per

Mathematics
1 answer:
BabaBlast [244]3 years ago
7 0

Answer: 1.98c + 2.28z = 58.43

Step-by-step explanation:

.

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Convert 2.7 miles to yards.
Darina [25.2K]

Answer:

the answer is 4752

Step-by-step explanation:

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3 years ago
Josie has a small fish tank shaped like a rectangular prism. Her fish tank measures 7 inches tall and 9 inches wide. If Josie's
irinina [24]

Answer:6

Step-by-step explanation:

If we know that the formula of a rectangular prism is length * width * height, and we know the height and width are 7 and 9, the length is the only thing that is left. The volume is 378, and so now we have:

length * 7 * 9 = 378. Dividing the 9 and 7, we get 378/(9*7). The length is 6.

3 0
3 years ago
2. You deposit $1200 into a bank account. Every year that accounts increase by 15 %.
lord [1]

Answer:

Exponential Growth, 1200(1.15)

Step-by-step explanation:

It is a Growth function because it is "increasing" yearly. The equation is multiplying with 1.15 because when it is increasing, you need to add 1 to the percentage rate.

7 0
3 years ago
If ab =9cm and bc =12 cm which does ac equal
Rama09 [41]
Just add them together
9 + 12 = 21
5 0
3 years ago
Use a triple integral to find the volume of the tetrahedron T bounded by the planes x+2y+z=2, x=2y, x=0 and z=0
Tanzania [10]

Answer:

Volume of the Tetrahedron T =\frac{1}{3}

Step-by-step explanation:

As given, The tetrahedron T is bounded by the planes x + 2y + z = 2, x = 2y, x = 0, and z = 0

We have,

z = 0 and x + 2y + z = 2

⇒ z = 2 - x - 2y

∴ The limits of z are :

0 ≤ z ≤ 2 - x - 2y

Now, in the xy- plane , the equations becomes

x + 2y = 2 , x = 2y , x = 0 ( As in xy- plane , z = 0)

Firstly , we find the intersection between the lines x = 2y and x + 2y = 2

∴ we get

2y + 2y = 2

⇒4y = 2

⇒y = \frac{2}{4} = \frac{1}{2} = 0.5

⇒x = 2(\frac{1}{2}) = 1

So, the intersection point is ( 1, 0.5)

As we have x = 0 and x = 1

∴ The limits of x are :

0 ≤ x ≤ 1

Also,

x = 2y

⇒y = \frac{x}{2}

and x + 2y = 2

⇒2y = 2 - x

⇒y = 1 - \frac{x}{2}

∴ The limits of y are :

\frac{x}{2} ≤ y ≤ 1 - \frac{x}{2}

So, we get

Volume = \int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}\int\limits^{2-x-2y}_{z=0} {dz} \, dy  \, dx

             = \int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{[z]}\limits^{2-x-2y}_0 {} \,   \, dy  \, dx

             = \int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{(2-x-2y)} \,   \, dy  \, dx

             = \int\limits^1_0 {[2y-xy-y^{2} ]}\limits^{1-\frac{x}{2}} _{\frac{x}{2} } {} \, \, dx

             = \int\limits^1_0 {[2(1-\frac{x}{2} - \frac{x}{2})  -x(1-\frac{x}{2} - \frac{x}{2}) -(1-\frac{x}{2}) ^{2}  + (\frac{x}{2} )^{2} ] {} \, \, dx

             = \int\limits^1_0 {(1 - 2x + x^{2} )} \, \, dx

             = {(x - x^{2}  + \frac{x^{3}}{3}  )}\limits^1_0

             = 1 - 1² + \frac{1^{3} }{3} - 0 + 0 - 0

             = 1 - 1 + \frac{1 }{3} =  \frac{1}{3}

So, we get

Volume =\frac{1}{3}

7 0
3 years ago
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