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Lerok [7]
1 year ago
10

Simplify Sinx + cosx/ cos²x - sin²x​

Mathematics
1 answer:
bonufazy [111]1 year ago
3 0

\dfrac{\sin x + \cos x}{\cos^2 x - \sin^2 x}\\ \\\\=\dfrac{\sin x + \cos x}{(\cos x + \sin x )\\\\(\cos x - \sin  x)}\\\\\\=\dfrac{1}{\cos x - \sin x}

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The line through (1,7) and (-6, 7) in point-slope form​
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A rectangular prism has a length of 7 m, a height of 5 m, and a volume of 140 m3. What is the width?
BigorU [14]

The question is incomplete because it was not properly and correctly arranged

Complete Question:

A rectangular prism has a length of 7 m, a height of 5 m, and a volume of 140 m³. What is the width? A prism has a length of 7 meters, width of w, and height of 5 meters.

Which steps are correct? Check all that apply.

a) Substitute the known values into the formula: 140 = 7(w)(5).

b) Substitute the known values into the formula: 7 = 140(w)(5).

c) Substitute the known values into the formula: 5 = 7(w)(140).

d) Solve for the unknown: w = 4 m.

e) Solve for the unknown: w = 7 m.

f) Solve for the unknown: w = 2 m.

Answer:

a) Substitute the known values into the formula: 140 = 7(w)(5).

d) Solve for the unknown: w = 4 m.

Step-by-step explanation:

The steps that are correct are Options a) and d). This is because:

Step 1

The volume of a rectangular prism is calculated as:

Volume of a rectangular prism = Length (l) × Width(w) × Height(h)

The unit of the volume or a rectangular prism is in cubic metres (m³)

In the question, we are asked to find the unknown value which is the width and we were given the following known values:

Length = 7 m,

Height = 5 m

Volume = 140 m³

Step 2

Solve for the unknown value( Width)

Volume of a rectangular prism = Length (L) × Width(W) × Height(H)

140m³ = 7m × Width(m) × 5m

140m³ = 35m² × Width(m)

Width(w) = 140m³ ÷ 35m²

Width(w) = 4m

Hence, the unknown Width(w) = 4m

From the above explanation we can see that the correct steps is Option a) and Option d)

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Answer:

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Step-by-step explanation:

Each term in this sequence is 4 more than the previous term.  Therefore we have an arithmetic sequence.

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