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3 years ago

11

If a pair of 6-sided dice is tossed, what is the probability that both dice will show a number that is a multiple of 3 (i.E. 3 o

r 6)

1 answer:

kondaur [170]3 years ago

5 0

There are 4 possibilities out of the 36 ways the dice can land:

... (3, 3), (3, 6), (6, 3), (6, 6)

Hence, the probability of an outcome in this set is 4/36 = 1/9.

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HELP FAST PLEASE!!!!!

lidiya [134]

Alright, lets get started.

The answer Sandra got is correct that is zero but there are some mistakes she made while writing steps.

$2 cot(\frac{-9\pi}{2}) = 2 cot(\frac{9\pi}{2})$ Incorrect step

Because as per even/odd identity,

Cot (-Θ) = - cot (Θ)

Hence

$2 cot (\frac{-9\pi}{2}) = - 2 cot (\frac{9\pi}{2})$

Now,

It could be written as

$-2 cot (\frac{9\pi}{2}) = -2 cot (\frac{\pi}{2})$

$-2 * 0$

0

Hence the answer is 0. : Answer

Hope it will help :)

3 0

3 years ago

A batch of 40 semiconductor chips is inspected by choosing a sample of 5 chips. Assume 10 of the chips do not conform to custome

butalik [34]

Answer:

a) 658008 samples

b) 274050 samples

c) 515502 samples

Step-by-step explanation:

a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.

So, the number of samples = ⁴⁰C₅ = 658008 samples

b) How many samples of 5 contain exactly one nonconforming chip?

There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways

¹⁰C₁ = 10 ways

then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways

³⁰C₄ = 27405 ways

So, total number of samples containing exactly 1 nonconforming chip in a sample of 5 = 10 × 27405 = 274050 samples

c) How many samples of 5 contain at least one nonconforming chip?

The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)

Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples

Total number of samples = 658008

The number of samples of 5 that contain at least one nonconforming chip = 658008 - 142506 = 515502 samples

6 0

3 years ago

You randomly select one card from a 52-card deckFind the probability of selecting a black ace or a red nine

rosijanka [135]

Answer:

2/52 + 2/52 = 4/52

6 0

3 years ago

Help please? its an exam

Nikolay [14]

Answer:

TU=4

Step-by-step explanation:

WU cuts the triangle in half (hint- angleTUW=90°)

so VU=TU

therefore, TU=4

5 0

3 years ago

What do you get when you cross the Atlantic with the titanic

n200080 [17]

A big mess in the ocean

3 0

3 years ago

Read 2 more answers