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3 years ago

2x-[4-3(2^5+18y)] simplify

Mathematics

2 answers:

Yanka [14]3 years ago

7 0

= 2<em />x<em> - </em>[4 - (96 + 54y)]
= 2x - 4 + 96 + 54y
= 2x + 54y + 92

MaRussiya [10]3 years ago

5 0

$2x-[4-3(2^5+18y)]\\\\=2x-[4-3(32+18y)]\\\\=2x-(4-96-54y)\\\\=2x-(-92-54y)\\\\=2x+92+54y$

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LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

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$\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill$

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2 years ago

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shtirl [24]

Answer:

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Step-by-step explanation:

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3 years ago

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aleksandr82 [10.1K]

Answer:

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Step-by-step explanation:

The constraints of the required linear equation are;

The point through which the line passes = (2, 2)

The line to which the required line is parallel = y = x + 4

Two lines are parallel if they have the same slope, therefore, we have;

The slope of the line, y = x + 4 is m = 1

Therefore, the slope of the required line = 1

The equation of the required lime in point and slope form becomes;

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∴ y = x - 2 + 2 = x

The equation of the required line is therefore, y = x

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3 years ago