What is the mean absolute deviation (MAD) of the set<br><br> [10, 15, 18, 8, 4]

34.98+12.24=?<br>answers please

Ksivusya [100]

Answer:

Hello!

After reading your question I have calculated the correct answer to be:

47.22

Step-by-step explanation:

The way I solved this equation was I first split the equation into two parts.

I took the two whole numbers, being "34" and "12", and made their own equation:

"34+12=?"

And then I took the two partial numbers "0.98" and "0.24" and made their own equation:

"0.98+0.24=?"

I then solved both equations:

"34+12= 46"

"0.98+0.24= 1.22"

And added those two solutions together to come up with the final solution:

"46+1.22= 47.22"

Hope this helped!

6 0

3 years ago

Mr. Bulky’s Candy Emporium sells all candy items for $0.60 per ounce. Penny and Ruth each bought several different types of cand

exis [7]

Answer: what’s the rest of the question? You didn’t provide enough data…✨

Step-by-step explanation:

4 0

3 years ago

jasmine bought 7 yards of fabric. The total cost was $45.43. What was the average cost per yard of the fabric she bought

torisob [31]

The answer would be $6.49.

4 0

3 years ago

Sami's bank account earns 4% simple interest per year. If Sami deposits $500, how much simple interest will she earn in four yea

Oksanka [162]

Answer:

20

Step-by-step explanation:

1% of 500 is 5

5*4(amount of years) = £20

3 0

3 years ago

Describe the translation of the function from the parent function f(x) = x².

kkurt [141]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\

\end{array}\\$

$\bf \begin{array}{llll}
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}
$

now, notice the template above... now let's see your function $\bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}$

so.. what do you think was the shift then?

8 0

3 years ago

What is the mean absolute deviation (MAD) of the set [10, 15, 18, 8, 4]