Answer:
X³-x
Step-by-step explanation:
Lcm
x(x-1)(x+1)
x(x²-1)
x³-x
1 is A - just plug and chug
2 is B - for 2 linear equations to have infinite solutions they mustbe the same
3 is C
4 is C - that is where they intersect
5 is A - same slope and different intercepts means no solutions
Answer:
Interest in 3 years = $456.52
Step-by-step explanation:
As we know the the formula of compound interest
Total amount = 
Here n = number of times amount is compounded
r = rate of interest
t = period
Here A = $2500
r = 0.0575
n = 1 (compounded annually)
t = 3 years
Therefore amount after 3 years
P =2500(1.0575)³
= 2500×1.18
= $2956.52
We have to calculate the interest then
Interest = $2956.52-$2500 = $456.52
So after 3 years interest gained = $456.52
Answer:
The center is -1,5 and the radius is 2
Step-by-step explanation:
Subtract 22 from both sides of the equation. x 2 + y 2 + 2 x − 10 y = − 22 Complete the square for x 2 + 2 x . ( x + 1 ) 2 − 1 Substitute ( x + 1 ) 2 − 1 for x 2 + 2 x in the equation x 2 + y 2 + 2 x − 10 y = − 22 . ( x + 1 ) 2 − 1 + y 2 − 10 y = − 22 Move − 1 to the right side of the equation by adding 1 to both sides. ( x + 1 ) 2 + y 2 − 10 y = − 22 + 1 Complete the square for y 2 − 10 y . ( y − 5 ) 2 − 25 Substitute ( y − 5 ) 2 − 25 for y 2 − 10 y in the equation x 2 + y 2 + 2 x − 10 y = − 22 . ( x + 1 ) 2 + ( y − 5 ) 2 − 25 = − 22 + 1 Move − 25 to the right side of the equation by adding 25 to both sides. ( x + 1 ) 2 + ( y − 5 ) 2 = − 22 + 1 + 25 Simplify − 22 + 1 + 25 . ( x + 1 ) 2 + ( y − 5 ) 2 = 4 This is the form of a circle. Use this form to determine the center and radius of the circle. ( x − h ) 2 + ( y − k ) 2 = r 2 Match the values in this circle to those of the standard form. The variable r represents the radius of the circle, h represents the x-offset from the origin, and k represents the y-offset from origin. r = 2 h = − 1 k = 5 The center of the circle is found at ( h , k ) . Center: ( − 1 , 5 ) These values represent the important values for graphing and analyzing a circle.
A variable is a letter, for example x, y or z, that represents an unspecified number.
6 + x = 12
To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12.
