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denpristay [2]
3 years ago
8

If three times a number added to 8 is divided by the number plus 7, the result is four thirds. Find the number.​

Mathematics
1 answer:
Marina86 [1]3 years ago
5 0

9514 1404 393

Answer:

  4/5

Step-by-step explanation:

The wording is ambiguous, as it often is when math expressions are described in English. We assume you intend ...

  \dfrac{3n+8}{n+7}=\dfrac{4}{3}\\\\3(3n+8)=4(n+7)\qquad\text{multiply by $3(n+7)$}\\\\9n+24=4n+28\qquad\text{eliminate parentheses}\\\\5n=4\qquad\text{subtract $4n+24$}\\\\\boxed{n=\dfrac{4}{5}}\qquad\text{divide by 5}

The number is 4/5.

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Robert has a number cube, a coin, and a (fair) spinner numbered 1 to 6.
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I think B because I think B
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What is 15 percent of 60
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9 %

Step-by-step explanation:

7 0
3 years ago
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write the equation of the line using the given information. type your awnser in slope intercept form,y=mx+b​
faltersainse [42]

Answer:

y=3/-1x+4

Step-by-step explanation:

Okay so first thing you need to know is that if there is an ordered pair (x, y) where x is 0, your y-intercept is your y. For example, your problem has (0, 4) your x is 0 and your y is 4. Therefore your y-intercept is 4 which is the b. To find your mx, or slope, you need to do (y2-y1)/(x2-x1). Your y2 will be your y in your second ordered pair and your y1 will be in your y in the first ordered pair. Same for your x. So, (4-1)/(0-1) which equals 3/-1. 3/-1 is your slope. So, your answer in slop intercept form is: y= 3/-1x+4. You could also try y= -3x+4 if that makes you more comfortable.

I know this is long this is my first time doing this lol.  

5 0
3 years ago
1. Three apples, a, and two peaches, p, sell for $1.25.
Simora [160]

Answer:

$0.25

Step-by-step explanation:

You can use systems of equations to solve this.

3a+2p = 1.25

5a+p = 1.5

Multiply the second equation by 2.

3a+2p = 1.25

10a+2p = 3

Subtract the bottom from the top

-7a= -1.75

Divide by -7

a= 0.25

Each apple is $0.25 (in this case, the peach also costs $0.25)

5 0
2 years ago
A book claims that more hockey players are born in January through March than in October through December. The following data sh
denis-greek [22]

Complete question :

Birth Month Frequency

January-March 67

April-June 56

July-September 30

October-December 37

Answer:

Yes, There is significant evidence to conclude that hockey​ players' birthdates are not uniformly distributed throughout the​ year.

Step-by-step explanation:

Observed value, O

Mean value, E

The test statistic :

χ² = (O - E)² / E

E = Σx / n = (67+56+30+37)/4 = 47.5

χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295

Degree of freedom = (Number of categories - 1) = 4 - 1 = 3

Using the Pvalue from Chisquare calculator :

χ² (18.295 ; df = 3) = 0.00038

Since the obtained Pvalue is so small ;

P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey​ players' birthdates are not uniformly distributed throughout the​ year.

5 0
2 years ago
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