The denominator can't equal 0.

The answer is D.
(11/2) x ((3/7) / (3/10)
(11/2) x (3/7) x (10/3)
330/42
7 6/7 or 7.857142857 ( or 7.86 rounded to nearest hundredth)
Answer:
No
Reasoning:
If something is a perfect cube, it is able to be put under a cube root (
) and will result in an integer (a non-decimal number > 0, basically).
So let's calculate
, and see if the result is an integer.
= 3.634.......
As you can see, the result is not an integer, therefore 48 is not a perfect cube.
Answer:
6 bucks
Step-by-step explanation:
210/35 = 6
210 dollars/ 35 hours = 6 dollars er hour