<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}
Answer:
3/10
Step-by-step explanation:
2/5 + x = 7/10
x = 7/10 - 2/5
x = 7/10 - 4/10
x = 3/10
Answer: 2/3
Step-by-step explanation:
There are three sectors of equal area. 2 is one of the sectors. You can get 3 and 4. There are two total cases out of 3, so it's 2/3
Hope that helped,
-sirswagger21
Answer:
option B : 12 degree
Step-by-step explanation:
The sum of angles in a triangle = 180 degree
Small box represents 90 degree
From the inner triangle
90 + angle y + 29 = 180 degree
90 + y + 29 = 180
119 + y = 180 (subtract 119 on both sides)
y= 61 degree
(y+x) is the top angle for bigger triangle
From the outer triangle , 90 + (y+x) + 17 = 180
We know y = 61
90 + (61+x) + 17 = 180
90 + 61 + x 17 = 180
168 +x = 180(subtract 168 on both sides)
x= 12 degrees
Answer:
no.
Step-by-step explanation:
the 4 on the sides are half the area of the ones of the top and bottom because if you take two small ones they will fit with one of the big ones.
sorry if I'm wrong.
