Answer:
The number of seniors who scored above 96% is 1.
Step-by-step explanation:
Consider the provided information.
Two percent of all seniors in a class of 50 have scored above 96% on an ext exam.
Now we need to find the number of seniors who scored above 96%
For this we need to find the two percent of 50.
2% of 50 can be calculated as:



Hence, the number of seniors who scored above 96% is 1.
Answer:
Median = 98
Step-by-step explanation:
Organize the numbers in order from least to greatest: 43,56,98,106,112.
Than begin crossing the numbers out
56,98,106
98
Answer:
Alternative C is the correct answer
Step-by-step explanation:
The first step is to determine the composite function;
![f[g(x)]](https://tex.z-dn.net/?f=f%5Bg%28x%29%5D)
![f[g(x)]=cos[cot(x)]](https://tex.z-dn.net/?f=f%5Bg%28x%29%5D%3Dcos%5Bcot%28x%29%5D)
We then employ a graphing utility to determine the range and the domain of the new function.
The range is the set of y-values for which the function is defined. In this case it is;
![[-1,1]](https://tex.z-dn.net/?f=%5B-1%2C1%5D)
On the other hand, the domain refers to the set of the x-values for which the function is real and defined. In this case; it is the set of real numbers x except x does not equal npi for all integers n.
Answer:
C
Step-by-step explanation:
Assume the surface area = 6x²
6 is the number of faces and x is the length of the cube
so 3/2 = 6x²
Divide by 6
1/4 = x²
Square root both sides
1/2 = x
Volume is : l×w×h
so 1/2 × 1/2 × 1/2 = 1/8
The given ratio of powder to water is 3:2 based on weight for Kool-aide. It is also given that 120g of flavored powder is needed for a certain amount of Kool-aide.
Let us assume that the amount of water (by weight) required to maintain the given ratio of 3:2 be represented by the letter
. Thus, from the given information we can conclude that:


Cross-multiplying we get:

grams.
Thus, the amount of water in grams in that Kool-aide is 80 grams.