<h3>
Answer:</h3>
6 hours
<h3>
Step-by-step explanation:</h3>
The two hoses together take 1/3 the time (4/12 = 1/3), so the two hoses together are equivalent to 3 of the first hose.
That is, the second hose is equivalent to 2 of the first hose. Two of the first hose could fill the vat in half the time one of them can, so 6 hours.
The second hose alone can fill the vat in 6 hours.
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The first hose's rate of doing work is ...
... (1 vat)/(12 hours) = (1/12) vat/hour
If h is the second hose's rate of doing work, then working together their rate is ...
... (1/12 vat/hour) + h = (1/4 vat/hour)
... h = (1/4 - 1/12) vat/hour = (3/12 -1/12) vat/hour = 2/12 vat/hour
... h = 1/6 vat/hour
so will take 6 hours to fill 1 vat.
Answer:
a, y =3/x
x = 0.5 => y = 3/0.5 = 6
x = 1 => y = 3/1 = 3
x = 2 => y = 3/2 = 1.5
x = 3 => y = 3/3 = 1
x = 4 => y = 3/4 = 0.75
b,
y = 3/x passes (0.5, 6) => A is correct
Hope this helps!
An inch or 2 so yeah if in shapes then around a rectangle
I'll finish this in a comment or get a mod to open it, but the way it reads, it beeps 67.2 times in those 12 hours. Did you mean per hour?
67.2 / 12 = 5.6
See comment below. The question is the number of beeps in 1 hour which is 5.6 <<<< Answer
Answer:
x=2
Step-by-step explanation:
y=-x+4 y=3x
3x=x+4
2x=4
x=2
(I hope this is the answer)
