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victus00 [196]
3 years ago
12

2x + 3 > 13 Whats the answer plz help

Mathematics
1 answer:
Naily [24]3 years ago
8 0

Answer:

In this case, you can simply treat the > sign like an = sign.  The only time you would need to worry about is when multiplying or dividing by negative numbers.

2x + 3 > 13

2x + 3 - 3 > 13 - 3

2x > 10

2x / 2 > 10 / 2

x > 5

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140/3 or 46.6(with the 6 repeating)

Step-by-step explanation:

(x+55)+(2x-15)=180

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During the summer Andrew worked for 5 days each week he worked 8 hours each day
Tema [17]
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Calculate the perimeter of this shape.<br> 12 cm<br> 18 cm
chubhunter [2.5K]

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3 0
3 years ago
Find all solutions of the equation: 2cos^2x-cosx=1
Art [367]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3166243

——————————

Solve the trigonometric equation:

     \mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}


Make a substitution:

     \mathsf{cos\,x=t\qquad (-1\le t\le 1)}

and the equation becomes

     \mathsf{2t^2-t-1=0}


Rewrite conveniently  – t  as  + t – 2t,  and then factor the left-hand side by grouping:

      \mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}


Factor out  2t + 1:

     \mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}


Substitute back for  t = cos x:

     \begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}


Therefore,

     \begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}

where  k  is an integer.


Solution set:   

\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}


I hope this helps. =)

3 0
3 years ago
Help me pleaseeeeeeeeee ​
ahrayia [7]

for 2 points A(xa;ya) and B(xb;yb)

the slope is (yb - ya) / (xb - xa)

here

the slope = 4 = (17-r) / (4-(-1))

(17-r) / 5 = 4

17 - r = 20

r = 17 - 20

r = - 3

point (-1 ; -3)

6 0
2 years ago
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