Question

Let HH represent the number of hummingbirds and SS represent the number of sunbirds that must pollinate the colony so it can survive until next year.
6H+4S > 746H+4S>74
This year, 88 hummingbirds pollinated the colony. What is the least number of sunbirds that must pollinate the colony to ensure that it will survive until next year?

Answer 1

Answer: 7

Step-by-step explanation:

Here the given inequality that shows the number of humming birds(H) and the number of sunbirds(S)  that must pollinate the colony so it can survive until next year,

6 H + 4 S > 74

If This year, 8 hummingbirds pollinated the colony.

By putting H=8 in the above inequality,

We get,

6× 8 + 4 S > 74

⇒ 48 + 4 S > 74

⇒ 4 S > 26

⇒ S > 6.5

Hence the least number of sunbirds is 7.

Answer 2

Answer:

S > 6.5 means a minimum of 7 sun birds must pollinate.

Step-by-step explanation:

Let H represent the number of hummingbirds and S represent the number of sun birds that must pollinate the colony so it can survive until next year.

Now the given inequality is :

$6H+4S>74$

This year, 8 hummingbirds pollinated the colony, means we will put H = 8 in the inequality.

$=> 6(8)+4S>74$

$=> 48+4S>74$

$=> 4S>74-48$

$=> 4S>26$

Hence, $S>6.5$

This, means a minimum of 7 sun birds must pollinate.