<span>The problem says that the distance D to the horizon is directly proportional to the square root of the elevation E of the observer, so:
</span>
The person who is 36 feet above the water ⇒ √36=6
A person 49 feet above the water ⇒ √49=7
<span>
So, by proportions, you have:
(7/6)x7.4= 8.63 miles
Therefore, the answer is: </span><span>a person 49 feet above the water can see 8.63 miles</span><span> </span>
3 and -3
hope l hlped u have a good day("
hope
#7 is VTU AND HFG
#8 is AAS
What's your question so I could help?