How do you use the elimination method ?

1 answer:

6 0

To use the elimination method, you have to create variables that have the same coefficient, then you can eliminate them.

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AleksandrR [38]

Yo mama is the answer.

3 0

2 years ago

Solve the equation. 2(y – 4) = 4 SHOW YOUR WORK!

ahrayia [7]

2(y−4)=4

(2)(y)+(2)(−4)=4

2y+−8=4

2y−8=4

2y−8+8=4+8

2y=12

$\frac{2y}{2}=\frac{12}{2}$

y=6 is correct answer.

Hope this helps!

Thanks!

8 0

2 years ago

solve the eqution 9.95+0.30s=c c is the amount of dollars a website charges for downloading songs s stands ffor number of songs

lutik1710 [3]

9.95 + 0.30s = C

9.95

9.95 + 10.5 = C

C = 20.45

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5 0

2 years ago

Answer in factored form 13+14m+m^2

natta225 [31]

<span>Solution

m = {-13, -1}</span>

5 0

3 years ago

Read 2 more answers

How do I do 8b(ii) ? Please help me thank you!

Mila [183]

Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.

7 0

3 years ago