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mamaluj [8]
3 years ago
15

What is the solution of the following linear system of equations? 4y=−5x−2, x−4y=14

Mathematics
1 answer:
Lisa [10]3 years ago
7 0

Answer:

X = 2 and Y = -3

Step-by-step explanation:

4y = -5x - 2

x - 4y = 14

5x + 4y = -2....... equation 1

x - 4y = 14........... equation 2

<u>Using Elimination </u><u>Method</u>

Add Equation 1 to Equation 2

6x = 12

Divide both side by 6

X= 2

Put X= 2 into Equation 1

5(2) + 4y = -2

10 + 4y = -2

4y = -2 - 10

4y = -12

Divide both side by 4

Y = -3

Therefore

x = 2

y = -3

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3 years ago
4/5 + 9/10 what is this answer?
RoseWind [281]

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The least common multiple of 5 and 10 is 10. Convert 4/5 and 9/10 to fractions with denominators of 10.

\boldsymbol{\sf{\dfrac{4\times2}{5\times2}+\dfrac{9}{10} \ \ \to \ \ Simplify }}

\boldsymbol{\sf{ \dfrac{8}{10}+\dfrac{9}{10}  }}

Since 8/10 and 9/10 have the same denominator, join their numerators to add them.

\boldsymbol{ \sf{\dfrac{8+9}{10} \ \to \ \  Add }}

Simplify

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3 0
2 years ago
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lbvjy [14]

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4 years ago
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Answer:

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we will have to do a trig sub for this

use x=a*tanθ for sqrt(x^2 +a^2) where a=2

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