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notka56 [123]
3 years ago
14

Ms. Chin asked her students to use the properties of multiplication to rewrite the expression (negative 5) (Negative StartFracti

on 2 over 7 EndFraction) Left-bracket (StartFraction 4 over 11 EndFraction) (negative 9) Right-bracket. The table below shows the properties that each of four students used to rewrite the expression.
Expressions Generated by Students
Student
Properties used to rewrite the expression
Mitul
Commutative property
Stacy
Associative property
Tom
Associative property and then the commutative property
Walt
Commutative property and then the associative property

How many of the students created an expression that was equivalent to the original?
one
two
three
four
Mathematics
2 answers:
12345 [234]3 years ago
4 0

Answer:

Three

Step-by-step explanation: :)

natali 33 [55]3 years ago
3 0

Answer:

three

Step-by-step explanation:

hope it hlps

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Factor completely 3bx^2 - 9x^3 - b + 3x​
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Factor out the common terms in the first two terms, then in the last two terms;

3x^2(b - 3x) - (b - 3x)

Factor out the common term b - 3x

<u>= (b - 3x)(3x^2 - 1)</u>

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out of these, it would be 4x - 4 * 2

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The length of a rectangle is 5 feet and the width is x the perimeter is less than 15 feet write and solve an inequality to find
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Answer:

5 ft * x ft

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Step-by-step explanation:

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Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court
Ksju [112]

Answer:

(a)\dfrac{92}{117}

(b)\dfrac{8}{39}

(c)\dfrac{25}{117}

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
  • Two women are appointed

P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

5 0
3 years ago
Please help me with my work
Mandarinka [93]

Answer

m = 19b

Step-by-step explanation:

Pretty Simple Fill In The Variables

5 Minute= 95 Blinks

95 Divided by 5 Is 19 So

M = 19b

They Want you to find what is the blinks per-minute

7 0
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