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2 years ago

. Find the GCF of the pair of numbers. 15 and 77

Mathematics

1 answer:

VikaD [51]2 years ago

6 0

Answer:

The GCF (Greatest Common Factor) of 15 and 77 is 1.

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Five-card poker hand is dealt at random from a standard 52-card deck.

Alisiya [41]

Answer:

Step-by-step explanation:

a) The probability that the hand contains exactly one ace

No of ways of selecting one ace and four non ace would be

= $4C1 (48C4)\\\\= 778320$

i.e. α=778320

b) the probability that the hand is a flush

No of ways of getting a flush is either all 5 hearts or clubs of spades or dice

= $4(13C5) = 5148$

ie. β=5148

c) the probability that the hand is a straight flush

In each of the suit to get a straight flush we must have either A,2,3,4,5 or 2,3,4,5,6, or .... or 9,10, J, q, K

So total no of ways = $=9(13C5) 4\\= 46332$

γ=46332

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3 years ago

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melisa1 [442]

Answer:

Heredity is the passage of traits from parent to offspring.

Heredity material is also known as DNA.

Heredity is responsible for traits such as eye color and skin color.

Step-by-step explanation:

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2 years ago

Find the sum.<br> 7/30 + 9/20 PLS

e-lub [12.9K]

Answer:

41/60

Step-by-step explanation:

Convert the fractions into like denominators: 7/30 = 140/600, 9/20 = 270/600

Add: 140/600+270/600 = 410/600

Divide into a smaller fraction: 41/60

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2 years ago

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xxTIMURxx [149]

Answer:

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Step-by-step explanation:

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2 years ago

Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation

lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=73$

Step-by-step explanation:

$First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}$

$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$

$S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\$

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73$

5 0

3 years ago

. Find the GCF of the pair of numbers. 15 and 77​

. Find the GCF of the pair of numbers. 15 and 77