Answer:

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

And we can solve for
and solving we got:

And from the previous result we got:

And solving we got:

And then we can find the mean with this formula:

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Step-by-step explanation:
For this case we know that the currently mean is 2.8 and is given by:

Where
represent the number of credits and
the grade for each subject. From this case we can find the following sum:

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

And we can solve for
and solving we got:

And from the previous result we got:

And solving we got:

And then we can find the mean with this formula:

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Answer:
-3<x<3
Step-by-step explanation:
let y=0
0=x^2-9
0=(x+3)(x-3)
x=-3 and x=+3
Answer:
Exact form: 3√5/5
Decimal form: 1.34164078...
Step-by-step explanation:
Answer:
82 inches
Step-by-step explanation:
The difference between consecutive even integers is 2, thus
let the legs be n and n + 2
Using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
n² + (n + 2)² = 58² ← expand and simplify left side
n² + n² + 4n + 4 = 3364 ( subtract 3364 from both sides )
2n² + 4n - 3360 = 0 ( divide all terms by 2 )
n² + 2n - 1680 = 0 ← in standard form
(n + 42)(n - 40) = 0 ← in factored form
Equate each factor to zero and solve for n
n + 42 = 0 ⇒ n = - 42
n - 40 = 0 ⇒ n = 40
But n > 0 ⇒ n = 40
and n + 2 = 40 + 2 = 42
Thus sum of legs = 40 + 42 = 82 inches