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fenix001 [56]
2 years ago
15

Maths question Write an algebraic expression for each of the following

Mathematics
1 answer:
kotykmax [81]2 years ago
8 0

Answer:

a) 3n+5

b) n+16

c) \frac{n-9}{2}

d) \frac{x-u}{x+u}

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480 into ratio 1:3:4
olga nikolaevna [1]

Step-by-step explanation:

60: 180: 240

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3 years ago
Could someone help i need it as soon as possible
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3 years ago
HELP PLEASE!!!!
Mice21 [21]
Area is length times width. In this case, if we use all 3300 feet of fence, the width (distance from the river to the fence opposite can be x, and the fence opposite the river will be 3300-2x (the total amount of fence, less the amount on the other two sides) so the area as a function of x to meet the specification of the problem will be:<span>
A(x)=x(3300−2x)=(43560)20</span><span>
It looks to me that you could turn it into a quadratic equation (ax^2+bx+c=0) and solve it....

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3 years ago
The length of a rectangle is
Marysya12 [62]

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2 years ago
According to chebyshev's theorem, the maximum proportion of data values from a data set that are more than 2 standard deviations
vodka [1.7K]
<span>All you have to do is learn Chebyshev's theorem in terms of k, then substitute 2 for k. Here is Chebyshev's theorem in terms of k: According to Chebyshev's theorem, the proportion of values from a data set that is further than standard deviations from the mean is at most . Then when you plug in 2 for k, you get: According to Chebyshev's theorem, the proportion of values from a data set that is further than standard deviations from the mean is at most . or writing for , According to Chebyshev's theorem, the proportion of values from a data set that is further than standard deviations from the mean is at most . Or if you prefer a decimal answer: According to Chebyshev's theorem, the proportion of values from a data set that is further than standard deviations from the mean is at most . Or if you prefer a percent answer: According to Chebyshev's theorem, the proportion of values from a data set that is further than standard deviations from the mean is at most %. </span>
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3 years ago
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