Answer:
The future value of this initial investment after the six year period is $2611.6552
Step-by-step explanation:
Consider the provided information.
A student desired to invest $1,540 into an investment at 9% compounded semiannually for 6 years.
Future value of an investment: 
Where Fv is the future value, p is the present value, r is the rate and n is the number of compounding periods.
9% compounded semiannually for 6 years.
Therefore, the value of r is: 
Number of periods are: 2 × 6 = 12
Now substitute the respective values in the above formula.




Hence, the future value of this initial investment after the six year period is $2611.6552
Answer:
C=14pi cm
A=49pi cm^2
Step-by-step explanation:
1) Circumference of a circle is 2piR and R=7cm
C=2pi(7)
C=14pi cm
2) Area of a circle is piR^2 and R=7cm
A=pi (7)^2
A=49pi cm^2
Answer: The numbers are 14, 16 and 18.
Step-by-step explanation: First thing to note is that consecutive even numbers have a difference of 2 units between every two terms. That is, if the first number is a, the next would be a + 2, and the next would be a + 4, and so on.
Therefore the three consecutive even numbers shall be a, a + 2, and a + 4.
Our equation now becomes;
a + a + 2 + a + 4 = 48
3a + 6 = 48
Subtract 6 from both sides of the equation
3a = 42
Divide both sides of the equation by 3
a = 14
Therefore, the numbers are 14, 16 and 18.