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melamori03 [73]
2 years ago
9

MATH WILL GIVE BRAINLIEST!

Mathematics
1 answer:
Mice21 [21]2 years ago
3 0

Answer:

-2x + 6 \leq 8x or 5x + 3 < 9

Step-by-step explanation:

-2x + 6 \leq 8x   -> x\geq 3/5

5x + 3 < 9       -> x < 6/5

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(3/2^a + 1/4a^2=3/2a^3)
AleksandrR [38]

Answer:

a  =  1.0478076

Step-by-step explanation:

Mark me brainiest plz

6 0
2 years ago
A bacteria culture starts with 160 bacteria and grows at a rate proportional to its size. After 5 hours there will be 800 bacter
Leona [35]

Answer:

Step-by-step explanation:

Let the rate at which the bacteria grow be represented by the exponential equation

P(t) = P0e^kt

P(t) is the population of the bacteria after time t

P0 is the initial population

k is the constant of variation

t is the time

If the initial Population is 160 bacteria's, them the equation becomes;

P(t) = 160e^kt

b) if After 5 hours there will be 800 bacteria, this means

at t = 5 p(t) = 800

Substitute and get k

800 = 160e^5k

800/160 = e^5k

5 = e^5k

Apply ln to both sides

Ln5 = lne^5k

ln5 = 5k

k = ln5/5

k = 0.3219

Next is to calculate the population after 7hrs i.e at t = 7

P(7) = 160e^0.3219(7)

P(7) = 160e^2.2532

P(7) = 160(9.5181)

P(7) = 1522.9

Hence the population after 7houra will be approximately 1523populations

c) To calculate the time it will take the population to reach 2790

When p(t) = 2790, t = ?

2790 = 160e^0.3219t

2790/160 = e^0.3219t

17.4375 = e^0.3219t

ln17.4375 = lne^0.3219t

2.8587 = 0.3219t

t = 2.8587/0.3219

t = 8.88 hrs

Hence it will take approximately 9hrs for the population to reach 2790

7 0
3 years ago
What is an equation of the line that passes through the point ( 8 , − 4 ) and is parallel to the line x − 4 y = 12 x−4y=12?
Natasha2012 [34]

Answer:

as the line is parallel we do not change x-4y what we change is the result x = 8 & y = -4 so the result is 8 - 4 (-4) = 24 so the equation is 24

8 0
3 years ago
76 less than the quotient of an unknown number and 5 is 116.
Reil [10]
76-(xdevided5)=116 That is my answer
3 0
2 years ago
Will someone help me with this
Marina CMI [18]

hope this helps :)

.........

3 0
1 year ago
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