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Fiesta28 [93]
3 years ago
8

What is the slope of the line?

Mathematics
1 answer:
andriy [413]3 years ago
5 0
I can’t see the numbers clear ?
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Determine the point on the graph of y = In 2x at which the tangent line is perpendicular to
Sveta_85 [38]

Answer:

  (1/4, ln(1/2))

Step-by-step explanation:

The slope of the given line is -1/4, so the perpendicular line will have a slope of -1/(-1/4) = 4.

The slope of the given function is its derivative:

  y' = 2/(2x) = 1/x

That will have a value of 4 when x = 1/4.

The point on the graph where the slope is 4 is (x, y) = (1/4, ln(1/2)).

6 0
4 years ago
Read 2 more answers
Please someone help me...​
kramer

Step-by-step explanation:

x cos θ + y sin θ = x cos β + y sin β

<em>Let's say x = cos A, and y = sin A.</em>

cos A cos θ + sin A sin θ = cos A cos β + sin A sin β

<em>Use angle sum formula.</em>

cos(A − θ) = cos(A − β)

A − θ = ±(A − β)

A − θ = β − A

2A = θ + β

A = (θ + β) / 2

cot A = cot((θ + β) / 2)

x/y = cot((θ + β) / 2)

4 0
3 years ago
Read 2 more answers
Question 21 of 25
Ivan

Answer:

b

Step-by-step explanation:

i would wait until someone eltse answers just to be sure

6 0
3 years ago
The solution of 12 + 2x – x = 9x + 28
Natalka [10]

Answer:

x = -2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

7 0
3 years ago
Read 2 more answers
The length of a rectangle is 4 m more than the width. The are is 30 m ^2. find the width and length.
zlopas [31]

Answer:

Step-by-step explanation:

AREA FORMULA: LENGTH * WIDTH

L*W=30

L=W+4 thus

(W+4)W=30

W^2+4W=30

W^2+4W-30=0

USING THE QUADRATIC EQUATION WE GET

X=(-B+-SQRT[B^2-4QC])/2A

X=(-4+-SQRT16-4*1*-30])/2*1

X=(-4+-SQRT16+120])/2

X=(-4+-SQRT136)/2

X=(-4+-11.66)/2

X=(-4+11.66)/2

X=7.66/2

X=3.83M IS THE WIDTH.

THUS THE LENGTH IS

L*3.83=30

L=30/3.83

L=7.83M IS THE LENGTH

6 0
3 years ago
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