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kondor19780726 [428]
3 years ago
8

How many squares are in the 20th case

Mathematics
1 answer:
pentagon [3]3 years ago
3 0

Answer:

total 20 squares in matrix of size 4×3

Step-by-step explanation:

in square of size 1×1

six squares of size 2×2

2 squares of size 3×3

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Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
Use the information to answer the questions.
Anna71 [15]

Answer:

Part 1) The length of two sides and the measure of the included angle (Side-Angle-Side)

Part 2) b^2=a^2+c^2-2(a)(c)cos(B)  

Part 3) b=11.6\ in

Step-by-step explanation:

we have

In the triangle ABC

a=11\ in\\c=9\ in\\B=70^o

Part 1) Which information about the triangle is given?

In this problem we have the length of two sides and the measure of the included angle (Side-Angle-Side)

see the attached figure to better understand the problem

Part 2) Which formula can you use ti find b?

I can use the law of cosines

b^2=a^2+c^2-2(a)(c)cos(B)  

we have

a=11\ in\\c=9\ in\\B=70^o

substitute the given values

b^2=11^2+9^2-2(11)(9)cos(70^o)

b^2=202-67.72  

b=11.59\ in

Part 3) What is b, rounded to the nearest tenth?

Remember that

To Round a number

a) Decide which is the last digit to keep  

b) Leave it the same if the next digit is less than 5 (this is called rounding down)  

c) But increase it by  1 if the next digit is  5 or more (this is called rounding up)

In this problem we have

11.59\ in

We want to keep the digit 5

The next digit is 9 which is 5 or more, so increase the "5" by 1 to "6"

therefore

b=11.6\ in

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3 years ago
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3 years ago
If a(2x-3) = bx+5 then the solution for x in terms of a and b is
Allisa [31]

Answer:

x=(3a+5)/(2a-b)

Step-by-step explanation:

We spread the a to the 2x and -3 first,

2ax -3a= bx+5 5ax

By adding 3a, we pass the -3a over

2ax=bx+5+3aa bx+5+3aa

We'll pass the bx over the bx, then

2ax-bx=5+3aa-bx=5

Now we will party like this on the left side,

5+3a) x(2a-b)=5+3a)

Everything we have to do to find x is to separate both sides by (2a-b)

x=(3a+5)/=(3a+5)/ (2a-b)

6 0
3 years ago
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Find the measure of Arc PQ
monitta

Answer:420

Step-by-step explanation:

5 0
2 years ago
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