3 years ago

How many squares are in the 20th case

Mathematics

1 answer:

pentagon [3]3 years ago

3 0

Answer:

total 20 squares in matrix of size 4×3

Step-by-step explanation:

in square of size 1×1

six squares of size 2×2

2 squares of size 3×3

You might be interested in

The sum of two numbers is 12. One number is prime and the other is composite. What are the numbers?

kompoz [17]

9 and 3. Because 9 is a composite number (3*3 = 9) and 3 is a composite number (1*3 = 3).

4 0

3 years ago

Read 2 more answers

12y+15=24-6y ??????????????????

lyudmila [28]

Answer:y=1/2

Step-by-step explanation:

7 0

3 years ago

Help me with this question

finlep [7]

Answer:

I THINK C

Step-by-step explanation:

I THINK.

4 0

3 years ago

Read 2 more answers

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$