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4 years ago

2.2. Name the two stages of photosynthesis

Chemistry

1 answer:

andre [41]4 years ago

6 0

Answer:

1. Light-dependent stage

2. Light-independent stage or Calvin cycle

Explanation:

Photosynthesis is the process by which plants and other autotrophic organisms synthesize their food (glucose) in the presence of sunlight as energy source. However, this photosynthetic process, which is a metabolic reaction occurs in two stages namely; Light-dependent stage and Light-independent stage.

- The light dependent stage occurs in the thylakoid membrane of the chloroplast. It involves the synthesis of NADPH and ATP needed for the light independent stage of photosynthesis.

- The light independent stage also known as Calvin cycle occurs in the stroma of the chloroplast. This is the stage where glucose is synthesized using inorganic source of carbon (CO2).

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How does a rock<br>Wither? Explain.

lesantik [10]

First, it combines with carbon dioxide in the soil to form a weak acid called carbonic acid. ... Carbonic acid slowly dissolves away minerals in rock, especially the carbonate minerals that make up limestone and marble. The weak acid decomposes the insoluble rock into watersoluble products that move into the groundwater.

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3 years ago

If 0.60 L of a solution contains 6.6 g of NaBr, what is its molar concentration?

-BARSIC- [3]

Answer:

Molarity = moles ÷ liters

to get moles of NaBr divide grams of NaBr by its molar mass (mass of Na + mass of Bromine)

Na = 22.989769

Br = 79.904

molar mass of NaBr = 102.893769

6.6g ÷ 102.893769 = 0.064143826 moles of NaBr

0.064143826 moles ÷ 0.60 liters = 0.1069 molar concentration or 11 %

7 0

3 years ago

Definition of a delocalised electron

Ray Of Light [21]

Answer:

Electrons in a metal that aren't bonded with only one atom

7 0

4 years ago

An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +

Maurinko [17]

Answer:

The simplified expression for the fraction is $\text {X} = \dfrac{ {k_3 \times cM} }{k_1 +k_2 + k_3 }$

Explanation:

From the given information:

O3* → O3 (1) fluorescence

O + O2 (2) decomposition

O3* + M → O3 + M (3) deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

$\text {X} = \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) } } }$

$\text {X} = \dfrac{ {k_3 \times cO \times cM} }{ {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) } }$

$\text {X} = \dfrac{ {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3 \times cM) }$

$\text {X} = \dfrac{ {k_3 \times cM} }{k_1 +k_2 + k_3 }$ since cM is the concentration of the inert molecule

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4 years ago

Which type of mixture can be separated using magnetism?

Tasya [4]

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4 years ago