Lizzie has 18 dimes and 12 quarters
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "q" be the number of quarters
We know that,
value of 1 dime = $ 0.10
value of 1 quarter = $ 0.25
Given that LIzzie has 30 coins
number of dimes + number of quarters = 30
d + q = 30 ---- eqn 1
Also given that the coins total $ 4.80
number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80

0.1d + 0.25q = 4.8 ------ eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 30 - q ---- eqn 3
Substitute eqn 3 in eqn 2
0.1(30 - q) + 0.25q = 4.8
3 - 0.1q + 0.25q = 4.8
0.15q = 1.8
<h3>q = 12</h3>
From eqn 3,
d = 30 - 12
<h3>d = 18</h3>
Thus she has 18 dimes and 12 quarters
Answer:
1,500 tickets in total (375 adult tickets and 1,125 children tickets)
Step-by-step explanation:
Let x be the number of adult tickets sold.
Three times as many children tickets were sold as adults, so 3x is the number of children tickets sold.
Children tickets were three dollars, so 3x children tickets cost 
Adult tickets were seven dollar, so x adult tickets cost 
The school sold $6000 worth of tickets.
Hence,

Answer:
0.75
Step-by-step explanation:
P(A | B) = P(A and B) / P(B)
P(vanilla | sundae) = P(vanilla and sundae) / P(sundae)
P(vanilla | sundae) = 0.15 / 0.2
P(vanilla | sundae) = 0.75
Answer:
$4.05
Step-by-step explanation:
45 x 9 = 4.05