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3 years ago

8

9. Simplify the following 9a + 8 - .25a

2 answers:

melisa1 [442]3 years ago

7 0

Step-by-step explanation:

I hope this helps. 9a+8-.25a = 8.75a+8

Dominik [7]3 years ago

4 0

Answer:

8.75 a + 8

Step-by-step explanation:

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Which is larger 12cm or 98mm

Usimov [2.4K]

To find out the answer, we must see how big a centimeter and milimeter is to a standard meter 1 cm = 0.01 m 1 mm = 0.001 m 12 cm = 0.12 m 98 mm = 0.098 m, 12 cm is bigger

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3 years ago

Find the measure of each missing angle explain work

BartSMP [9]

Angle 1: 52 degrees
angle 2: 79 degrees
angle 3: 38 degrees

explanation:
angle 1: 180 - 90 - 38 = 52
angle 2: 180 - 63 - 38 = 79
angle 3: 90 - 52

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3 years ago

Algebra problem, please help

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6 • x + 6 • 9

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3 years ago

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Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

strojnjashka [21]

Answer:

The missing side is $B = 6.0\ cm$

The missing angles are $\alpha = 56.2$ and $\theta = 93.8$

Step-by-step explanation:

Given

$A = 10\ cm$

$C = 12\ cm$

$\beta = 30$

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with $\alpha$

Angle B with $\beta$

Angle C with $\theta$

Calculating B

This will be calculated using cosine formula as thus;

$B^2 = A^2 + C^2 - 2ACCos\beta$

Substitute values for A, C and $\beta$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30$

$B^2 = 100 + 144 - 240 * 0.8660$

$B^2 = 100 + 144 - 207.8$

$B^2 = 36.2$

Take Square root of both sides

$B = \sqrt{36.2}$

$B = 6.0$ <em>(Approximated)</em>

Calculating $\alpha$

This will be calculated using cosine formula as thus;

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute values for A, B and C

$A^2 = B^2 + C^2 - 2BCCos\alpha$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha$

$100 = 36 + 144 - 144Cos\alpha$

Collect Like Terms

$100 - 36 - 144 = -144Cos\alpha$

$-80 = -144Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = Cos\alpha$

$0.5556 = Cos\alpha$

$\alpha = cos^{-1}(0.5556)$

$\alpha = 56.2$ <em>(Approximated)</em>

Calculating $\theta$

This will be calculated using cosine formula as thus;

$C^2 = B^2 + A^2 - 2BACos\theta$

Substitute values for A, B and C

$12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta$

$144 = 36 + 100 - 120Cos\theta$

Collect Like Terms

$144 - 36 - 100 = -120Cos\theta$

$8 = -120Cos\theta$

Divide both sides by -120

$\frac{8}{-120} = Cos\theta$

$-0.0667= Cos\theta$

$\theta = cos^{-1}(-0.0667)$

$\theta = 93.8$ <em>(Approximated)</em>

4 0

4 years ago

2x+5 is greater than 50

katrin2010 [14]

2x+5=50
-5 -5
—————-
2x = 45
Divide by 2
45/2 = 22.5
I hope this makes sense

6 0

3 years ago

Read 2 more answers